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4 years ago

Which expression shows the result of applying the distributive property to 12(5y + 4)

1 answer:

7 0

If we were to distribute the 12 to the 5y and 4, we would get the answer 60y + 48 A.

12(5y +4) = 12*5y + 12*4

60y + 12*4
60y + 48
A.

Hope I could help you out!
Have a good one, and God bless you!

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4 years ago

Amran is helping her sixth grade classmates get ready for their math test by making them identical Packages of pencils and calcu

Sholpan [36]

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3 years ago

I need help with part B plz help me asap

Sloan [31]

Answer:

see below PLEASE GIVE BRAINLIEST!!

Step-by-step explanation:

A) 2.40A ≦ 9.60

B) You can choose to purchase between 0 and 4 avacados. 4 is the maximum you can buy because 2.40 x 4 = 9.60 and that is all the money you have and more than 4 would make the equation incorrect. 0 is the least you can buy since you can't purchase a negative amount of something.

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4 years ago

Does each function describe exponential growth or decay?

Aleksandr [31]

<h3>Answer: Only first two are exponential growth function and last three functions are exponential decay functions.</h3>

Step-by-step explanation: We need to describe exponential growth or decay for the given functions.

The standard exponential function equation is

$y=a(b)^x$ .

Where a is the initial value and b is the growth factor.

Note: If value of b > 1, it would be an exponential growth and if b < 1, it would be an exponential decay.

Let us check them one by one.

$y=(1.008^{1/12}})^{12t}$ => $y=(1.008^})^{1/12\times{12t} }$

=> $y= (1.008)^t$ .

Value of b is 1.008 > 1, therefor it's an exponential growth function.

y=250(1+0.004)^t, also have b>1 therefor it's an exponential growth function.

All other functions has b values less than 1, therefore only first two are exponential growth function and last three functions are exponential decay functions.

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4 years ago

There are 27 students in Ms. Langley's

Yuliya22 [10]

Answer:

405 Problems

Step-by-step explanation:

One student in class has 15 problems.

There are 27 students in the class.

Let's <u>multiply</u> 15 by 27.

$15*27=405$

<em>In all, there would be 405 problems assigned to the whole class.</em>

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3 years ago