![x+100y=750 \\ x+150y=1050 \\ 50y=300 \\ y=6 \\ x=750-600=150](https://tex.z-dn.net/?f=x%2B100y%3D750%20%5C%5C%20x%2B150y%3D1050%20%5C%5C%2050y%3D300%20%5C%5C%20y%3D6%20%5C%5C%20x%3D750-600%3D150)
The fixed cost is $150, while the per-student cost is $6.
Given that a polynomial function P(x) has rational coefficients.
Two roots are already given which are i and 7+8i,
Now we have to find two additional roots of P(x)=0
Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.
conjugate of a+bi is given by a-bi
So using that logic, conjugate of i is i
also conjugate of 7+8i is 7-8i
Hence final answer for the remaining roots are (-i) and (7-8i).
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
![6x^3+6](https://tex.z-dn.net/?f=6x%5E3%2B6)
Now, by factorising , we get
![6x^3+6\\=6(x^3+1)](https://tex.z-dn.net/?f=6x%5E3%2B6%5C%5C%3D6%28x%5E3%2B1%29)
Now, we use the formula i.e.
![a^3+b^3=(a+b)(a^2-ab+b^2)](https://tex.z-dn.net/?f=a%5E3%2Bb%5E3%3D%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29)
By using this, we get ,
![6(x^3+1)\\=6(x+1)(x^2-x+1)](https://tex.z-dn.net/?f=6%28x%5E3%2B1%29%5C%5C%3D6%28x%2B1%29%28x%5E2-x%2B1%29)
So,
![(x+1) \text{ is the factor of }6x^3+6.](https://tex.z-dn.net/?f=%28x%2B1%29%20%5Ctext%7B%20is%20the%20factor%20of%20%7D6x%5E3%2B6.)
Answer:
B)7+n
Step-by-step explanation:
Answer:
564 patrons.
Step-by-step explanation:
20,304/36 = 564