Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
<u>Answer</u>
y = (1/2)x - 1
<u>Explanation</u>
The first step is to get the gradient of the line.
The two points in the line are; (2,0) and (-2, -2).
Gradient = (-2 - 0)/(-2, - 2)
= -2/-4
= 1/2
To get the function we use one of the point (2,0) and a general point (x,y).
1/2 = (y - 0)/(x - 2)
1/2 = y/(x - 2)
(x - 2) = 2y
2y = x - 2
y = (1/2)x - 1
Answer:
8+x if x > -8
8 if x = 0
-8-x if x < -8
Step-by-step explanation:
|14−(6-x)|
|14−6+x|
|8+x|
8+x if x > -8
8 if x = 0
-8-x if x < -8
Answer:
1996
Step-by-step explanation:
To find the number of terms in an arithmetic sequence, divide the common difference into the difference between the last and first terms, and then add 1.
2008 - 13 = 1995 + 1 = 1996
