104.002 i think this is the answer
Answer:
<em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>uh</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em>
(-3,-2)
You just change the signs
Answer:
C.
Step-by-step explanation:
= ![\sqrt[3]{8}^{x}\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%5E%7Bx%7D%5C%5C)
= Since ![\sqrt[3]{} = ^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D%20%3D%20%5E%7B1%2F3%7D)
= So, It becomes :
= 
Answer:
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).