Answer:
square root of 29 or approximately 5.38
Answer:
x = 0
Step-by-step explanation:
If p is a number other than zero, then

only if x=0.
Answer:
5x^4
Step-by-step explanation:
Answer: Its factored form will be

Step-by-step explanation:
Since we have given that

So, we need to factor ,

Now,

Now, by hit and trial method, we put n=1,


So, n-1 is also factor of p(n).
Now,

So, its factored form will be

Answer: c
Step-by-step explanation: