HEs going to have 14 dollars left
2x3=6
20-6=14
Answer:
$7803.72
Step-by-step explanation:
We have been given that a silo is in the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cubic meter. We are asked to find the total cost to fill the silo with soybeans.
First of all, we will find the volume of silo using volume of cone formula.
, where,
r = radius
h = Height
We know that radius is half the diameter, so radius of silo would be
.
![\text{Volume of cone}=\frac{1}{3}\pi (1.5\text{ m})^2 (8)\text{ m}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cone%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20%281.5%5Ctext%7B%20m%7D%29%5E2%20%288%29%5Ctext%7B%20m%7D)
![\text{Volume of cone}=\frac{1}{3}\pi\times 2.25\text{ m}^2 (8)\text{ m}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cone%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%5Ctimes%202.25%5Ctext%7B%20m%7D%5E2%20%288%29%5Ctext%7B%20m%7D)
![\text{Volume of cone}=\pi\times 0.75\text{ m}^2 (8)\text{ m}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cone%7D%3D%5Cpi%5Ctimes%200.75%5Ctext%7B%20m%7D%5E2%20%288%29%5Ctext%7B%20m%7D)
![\text{Volume of cone}=\pi\times 6\text{ m}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cone%7D%3D%5Cpi%5Ctimes%206%5Ctext%7B%20m%7D%5E3)
![\text{Volume of cone}=18.8495559\text{ m}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20cone%7D%3D18.8495559%5Ctext%7B%20m%7D%5E3)
Now we will multiply total volume by $414 to find total cost.\
![\text{Total cost of soybeans}=\$414 \times 18.8495559](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20cost%20of%20soybeans%7D%3D%5C%24414%20%5Ctimes%2018.8495559)
![\text{Total cost of soybeans}=\$7803.7161426](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20cost%20of%20soybeans%7D%3D%5C%247803.7161426)
![\text{Total cost of soybeans}\approx \$7803.72](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20cost%20of%20soybeans%7D%5Capprox%20%5C%247803.72)
Therefore, it will cost $7803.72 to fill the silo with soybeans.
Answer:
Step-by-step explanation:
Method 1: Calculate 40% discount on original price, then subtract discount from original price.
Amount of discount = 40% of $30
= 0.40 × $30
= $12
New price = $30 - $12 = $18
Method 2:
New price = (100% - discount percentage) of original price
= 60% of original price
= 0.60 × $30
= $18
4" x 2500 ft², namely 4 ft x 2500 ft², will just be 4*2500*ft*ft², or 10000 ft³.
![\bf \begin{array}{ll} yd&3ft\\\\ (yd)^2&(3ft)^2\\ &(3^2ft^2)\\ &9ft^2\\\\ (yd)^3&(3ft)^3\\ &(3^3ft^3)\\ &27ft^3 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bll%7D%0Ayd%263ft%5C%5C%5C%5C%0A%28yd%29%5E2%26%283ft%29%5E2%5C%5C%0A%26%283%5E2ft%5E2%29%5C%5C%0A%269ft%5E2%5C%5C%5C%5C%0A%28yd%29%5E3%26%283ft%29%5E3%5C%5C%0A%26%283%5E3ft%5E3%29%5C%5C%0A%2627ft%5E3%0A%5Cend%7Barray%7D)
since there are 27 ft³ in 1 yd³, then how many yd³ are there in 10000 ft³?
10000/27, that many yd³.