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Ratling [72]
3 years ago
11

You typically buy all of your groceries at Grocery Mart. This week, your favorite cereal is on sale there, 4 boxes for $10. At F

ood Market, where you don’t typically shop, the same cereal is on sale for $2.25 a box.
Mathematics
1 answer:
julia-pushkina [17]3 years ago
8 0

Answer:

B. Food market

Step-by-step explanation:

You typically buy all of your groceries at Grocery Mart. This week, your favorite cereal is on sale there, 4 boxes for $10. At Food Market, where you don’t typically shop, the same cereal is on sale for $2.25 a box. Based on price, which is the better value option?

A.Grocery Mart

B. Food Market

Grocery market:

4 boxes for $10

Unit price = cost / quantity

= $10 / 4 boxes

= $2.50 per box

Food market:

Price per box = $2.25

The better value option based on price is food market because it cost less to buy a box of cereal than grocery mart

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Solve s=2(lw+lh+wh) for w
Scilla [17]

                                                                   s = 2(lw + lh + wh)

Divide each side by  2 :                            s/2 = lw + lh + wh

Subtract 'lh' from each side:                s/2 - lh = lw + wh

Combine the 'w' terms:                        s/2 - lh = w(l + h)

Divide each side by (l + h):  (s/2 - lh) / (l + h) = w

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3 years ago
Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} }

but we will find sample size "n"

\sqrt{n}  = \frac{z_{a} S.D}{maximum error}

Squaring on both sides , we get

n  = (\frac{z_{a} S.D}{maximum error})^2

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

n  = (\frac{z_{a} p(1-p)}{maximum error})^2

n≤ (\frac{2.56X\frac{1}{2} }{0.02}) ^{2}    ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is  n = 4225

<u>verification</u>:-

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} } = \frac{2.56 1/2}{\ \sqrt{4225} }  = 0.0196

substitute all values and simplify we get maximum error is 0.02

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3 years ago
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Answer:

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