Answer:
B
Step-by-step explanation:
I might be wrong but im pretty sure the answer is B.
Answer:
80
Step-by-step explanation:
50 problems/x total = 62.5%
50/62.5=0.8 problem for each percent
0.8 * 100 percent = 80 problems
Answer:
2.86 quarts ( approx )
Step-by-step explanation:
Given,
The initial quantity of the Mr. Gittleboro's radiator that contains 30% antifreeze = 10 quarts,
Let x quarts of pure antifreeze replaced x quarts of Mr. Gittleboro's radiator to bring it up to a required 50% antifreeze,
So, the quantity of 30% antifreeze radiator after drained off x quarts = (10-x) quarts
Also, the quantity of final antifreeze radiator 50% antifreeze = 10 quarts
Thus, we can write,
30% of (10-x) + 100% of x = 50% of 10
30(10-x) + 100x = 500
300 - 30x + 100x = 500
300 + 70x = 500
70x = 200
x = 2.85714285714 quarts ≈ 2.86 quarts
Answer:
Step-by-step explanation:
First we need the length of the hypotenuse.
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
29 = c
If you are using angle B as your theta (angle from which the relations are formed:
a) sin = O/H = 20/29
b) cos = A/H = 21/29
c) tan = O/A = 20/21
