All categories

3 years ago

Question in the picture!

Mathematics

2 answers:

Aleonysh [2.5K]3 years ago

8 0

Answer:

Step-by-step explanation:

Ksju [112]3 years ago

4 0

Answer:

The answer is D 2 9/10

Step-by-step explanation:

Convert the Mixed numbers into improper fractions

then find the LCD (lowest common denominator) and combine

You might be interested in

Y = -5x + 15 2x + y = 12

Nana76 [90]

Answer:

x = 1, y = 10

Step-by-step explanation:

y = -5x + 15 --- Equation 1

2x + y = 12 --- Equation 2

Substitute y = -5x + 15 into Equation 2:

2x + y = 12

2x - 5x + 15 = 12

Evaluate like terms.

15 - 3x = 12

Isolate -3x.

-3x = 12 - 15

Evaluate like terms.

-3x = -3

Find x.

x = -3 ÷ -3

x = 1

Substitute x = 1 into Equation 2:

2x + y = 12

2(1) + y = 12

2 + y = 12

Isolate y.

y = 12 - 2

y = 10

4 0

3 years ago

Read 2 more answers

PLEASE HELP. WILL GIVE BRAINLY

zepelin [54]

For these questions it is asking you to convert different measurements.
For the first part,
You must convert 10 kilometres to meters
Or 500 meters to kilometres
For this example I will covert 500 meters to kilometres
1000 meters = 1 kilometer
So 500 meters is 0.5 kilometres or half a kilometer
So on the first day you ride 10 kilometres and increase by 0.5 kilometres a day that means you increase by 1 kilometer every two days
The question is asking how many days until you get to 15 kilometres well
15-10=5
5x2 =10 so the answer to the first part is 10 days

In the second part you have to convert again I am going to convert kilometres to meters this time
We know 1km = 1000m
So you times the kilometer by 1000 to get the meters
0.75 x 1000 = 750
So you start with 7500 and increase by 750 every day
The question asks you the total after 3 days so we must find out each day and add them up
1st day: 7500
2nd day: 7500+750=8250
3rd day: 8250+750=9000
Now we must add them together so
7500+8250+9000=24750
So the answer to this part is 24750 meters

The last part is asking you to compare the programs so let’s start with training program A
20-10=10
10x2= 20
So A is 20 days

Training program B:
We know from previous questions that on the third day you do 9000 meters so we must carry on from there
4th day: 9000+750=9750
5th day: 9750 +750=10500
6th day: 10500 + 750=11250
7th day: 11250 + 750 = 12000
As you can see there is a pattern here on the 3rd day we are on 9000 and on the 7th day we are on 12000 that means it has increased by 3000 in 4 days this is because 750 x 4 = 3000
This means we know 18000 is the 15th day
We will carry on from here
16th day: 18000+750=18750
17th day: 18760+750=19500
18th day: 19500+750=20250
Here we have gone over 200000 which is 20 km on the 18th day meaning training program B is quicker

8 0

3 years ago

6 numbers are shown

Sonja [21]

Answer:

$-1\frac{1}{2}$ , $-\frac{3}{4}$ , $-\frac{37}{50}$ , $\frac{5}{4}$ , $1\frac{1}{4}$ , $2\frac{3}{4}$

Step-by-step explanation:

$1\frac{1}{4}$ , $-1\frac{1}{2}$ , $-\frac{37}{50}$ , $-\frac{3}{4}$ , $2\frac{3}{4}$ , $\frac{5}{4}$

Order everything, negative to the left side and positive to the right side

Negative numbers:

$-1\frac{1}{2}$ , $-\frac{37}{50}$ , $-\frac{3}{4}$

Positive numbers:

$1\frac{1}{4}$ , $2\frac{3}{4}$ , $\frac{5}{4}$

Now order it on a number line:

$-1\frac{1}{2}$ , $-\frac{3}{4}$ , $-\frac{37}{50}$ , $\frac{5}{4}$ , $1\frac{1}{4}$ , $2\frac{3}{4}$

8 0

3 years ago

The random variable X is exponentially distributed, where X represents the waiting time to be seated at a restaurant during the

erastova [34]

Answer:

The probability that the wait time is greater than 14 minutes is 0.4786.

Step-by-step explanation:

The random variable X is defined as the waiting time to be seated at a restaurant during the evening.

The average waiting time is, β = 19 minutes.

The random variable X follows an Exponential distribution with parameter $\lambda=\frac{1}{\beta}=\frac{1}{19}$ .

The probability distribution function of X is:

$f(x)=\lambda e^{-\lambda x};\ x=0,1,2,3...$

Compute the value of the event (X > 14) as follows:

$P(X>14)=\int\limits^{\infty}_{14} {\lambda e^{-\lambda x}} \, dx=\lambda \int\limits^{\infty}_{14} {e^{-\lambda x}} \, dx\\=\lambda |\frac{e^{-\lambda x}}{-\lambda}|^{\infty}_{14}=e^{-\frac{1}{19} \times14}-0\\=0.4786$

Thus, the probability that the wait time is greater than 14 minutes is 0.4786.

7 0

3 years ago

Can someone please help? i don’t know how to solve this.

Charra [1.4K]

Answer:

Hey there!

We have the absolute value of x is greater than two.

Thus, to solve absolute value inequalities, we want to break the inequality down.

We break this down to

x>2

x<-2

Thus, we don't need to simplify this any further, and have our answer.

Hope this helps :)

8 0

3 years ago

Read 2 more answers