How do ypu slove dis? y^2(q-4) - c(q - 4)

Mathematics

1 answer:

Annette [7]4 years ago

4 0

y2(q-4)-c(q-4) Final result : (q - 4) • (y2 - c)

Step by step solution :Step 1 :Equation at the end of step 1 : ((y2) • (q - 4)) - c • (q - 4) Step 2 :Equation at the end of step 2 : y2 • (q - 4) - c • (q - 4) Step 3 :Pulling out like terms :

3.1 Pull out q-4

After pulling out, we are left with :
(q-4) • ( y2 * 1 +( c * (-1) ))

Trying to factor as a Difference of Squares :

3.2 Factoring: y2-c

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =
 A2 - AB + BA - B2 =
 A2 - AB + AB - B2 =
 A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : y2 is the square of y1 

Check : c1 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares

Final result : (q - 4) • (y2 - c)

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valina [46]

Answer:

Step-by-step explanation:

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From the photo,

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G = 34 degrees