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motikmotik
3 years ago
8

How do ypu slove dis? y^2(q-4) - c(q - 4)

Mathematics
1 answer:
Annette [7]3 years ago
4 0
<span><span> y2(q-4)-c(q-4)</span> </span>Final result :<span> (q - 4) • (y2 - c) </span>

Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span><span> ((y2) • (q - 4)) - c • (q - 4) </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> y2 • (q - 4) - c • (q - 4) </span><span>Step  3  :</span>Pulling out like terms :

<span> 3.1 </span>     Pull out     q-4 

After pulling out, we are left with : 
      (q-4) • (<span> y2</span>  *  1 +( c  *  (-1) ))

Trying to factor as a Difference of Squares :

<span> 3.2 </span>     Factoring: <span> y2-c</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check : <span> y2  </span>is the square of <span> y1 </span>

Check :<span> <span> c1  </span> is not a square !! 
</span>Ruling : Binomial can not be factored as the difference of two perfect squares

Final result :<span> (q - 4) • (y2 - c) </span><span>
</span>
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