Answer:
6 for c and 3 for h
Step-by-step explanation:
6*3+3*2
Answer:
7.5 ft³/min
Step-by-step explanation:
Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.
Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²
So, V = Ah = 2h = 2(10 - x)
The rate of change of volume is thus
dV/dt = d[2(10 - x)]/dt = -2dx/dt
Since dV/dt = 15 ft³/min,
dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min
Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt
= -dx/dt
= -(-7.5 ft³/min)
= 7.5 ft³/min
And the height at this point when x = 8 inches = 8 in × 1 ft/12 in = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft
6/12=X/18
Using the ratio of 18:12, you multiply 18/12 with 6, which equals 9.
Answer: NJ=9
Answer:
Center = (2,5)
Radius = 10
Choice A
To find this answer, first write the equation
(x-2)^2 + (y-5)^2 = 100
into
(x-2)^2 + (y-5)^2 = 10^2
Note how the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
We see that (h,k) = (2,5) is the center
and r = 10 is the radius
5∛x + 4 = 44
5∛x = 40
∛x = 8
x = 8^3
x = 512
answer
C. 512
