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Zinaida [17]
3 years ago
12

I need help with this one.

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

y = 3x + 5

Step-by-step explanation:

The equation in slope- intercept form is

y = mx + c

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, - 1) and (x₂, y₂ ) = (2, 11) ← 2 ordered pairs from the table

m = \frac{11+1}{2+2} = \frac{12}{4} = 3, thus

y = 3x + c ← is the partial equation

To find c substitute any ordered pair from the table into the partial equation

Using (2, 11 ), then

11 = 6 + c ⇒ c = 11 - 6 = 5

y = 3x + 5 ← equation of linear function

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The length is 45m and the width is 15m. Hope I was able to help

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d1i1m1o1n [39]

Answer:

a = 8 (to nearest whole number)

Step-by-step explanation:

Given:

m<B = 36°

m<C = 104°

c = 12

Required:

a

SOLUTION:

✔️First find m<A:

m<A = 180 - (104 + 36)

m<A = 40°

✔️Find a using Sine Rule:

Thus:

\frac{a}{sin(A)} = \frac{c}{sin(C)}

Plug in the values

\frac{a}{sin(40)} = \frac{12}{sin(104)}

Multiply both sides by sin(40)

\frac{a}{sin(40)} * sin(40) = \frac{12}{sin(104)} * sin(40)

a = \frac{12*sin(40)}{sin(104)}

a = 8 (nearest whole number)

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2 years ago
In right-angled ∆ ABC, ∟B=90⁰. ∆ ABC is in the first and second quadrant on the graph paper. The coordinates of the points A and
Musya8 [376]

Answer:

The given coordinates of the points A and C of the right triangle ABC are (2, 5) and (-2, 3) respectively

The possible pairs of the coordinates of the point B are found as follows;

1) Draw a horizontal line from the point C to the right and a vertical line down from the point A to get the point B at (2, 3) which is the point of the perpendicular intersection of the two constructed lines above

2) Draw a vertical line from the point C upwards and a horizontal line to the left from the point A to get the point B at (-2, 5) which is the point of the  perpendicular intersection of the two newly constructed lines here

Step-by-step explanation:

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Answer:

(0,-22)

Step-by-step explanation:

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Mr. Johnson was born in June 1971 and earns R47 400,00 which on the last day
Yuliya22 [10]

2.1.1. An IRP5 is the employee's tax certificate, detailing all the employee-related incomes, deductions, and related taxes.  The IRP5 assists the employee in making his tax returns for the subsequent year.

2.1.2. Mr. Johnson's taxable income for the year is <u>R490,414,56</u>.

2.1.3 Mr. Johnson's medical credit for the financial year is <u>R33,600</u>.

2.1.4 The annual tax payable by Mr. Johnson for the financial year from 1 March 2021 to 28 February 2022 is <u>R118,988,24</u>.

2.1.5 Calculate Mr. Johnson's monthly taxes are <u>R9,915,69</u>.

<h3>Data and Calculations:</h3>

Gross Pay = R47,400,00

Pension fund contributions = 7.5% (R3,555,00)

WVF contribution = 1% (R177,12)

Medical aid contributions = R2,800

Annual medical credit = R33,600 (R2,800 x 12)

Total deductions = R6,532,12 (R3,555,00 + R177,12 + R2,800)

Taxable income = R40,867,88 (R47,400 - R6,532,12)

Annual taxable income = R490,414,56 (R40,867,88 x 12)

<h3>Johnson's Tax liability:</h3>

Annual tax liability = R110 739 + 36% of taxable income above R467 500

= R110,739 + 36% of R22,914,56 (R490,414,56 - R467,500)

= R110,739 + R8,249,24

= R118,988,24

Monthly Tax = R9,915,69 (R118,988,24/12)

Thus, the taxable income (gross pay minus deductions)  forms the basis for determining the tax payable by Mr. Johnson during the tax year.

Learn more about taxable income at brainly.com/question/25307637

#SPJ1

<h3>Question Completion:</h3>

<u>Appendix A (Tax Rates)</u>

Taxable Income              Rate of tax (R)

R1 – R216 200                18% of taxable income

R216 201 – R337 800    R38 916 + 26% of taxable income above R216 200

R337 801 – R467 500   R70 532 + 31% of taxable income above R337 800

R467 501 – R613 600   R110 739 + 36% of taxable income above R467 500

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