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Zinaida [17]
3 years ago
12

I need help with this one.

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

y = 3x + 5

Step-by-step explanation:

The equation in slope- intercept form is

y = mx + c

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, - 1) and (x₂, y₂ ) = (2, 11) ← 2 ordered pairs from the table

m = \frac{11+1}{2+2} = \frac{12}{4} = 3, thus

y = 3x + c ← is the partial equation

To find c substitute any ordered pair from the table into the partial equation

Using (2, 11 ), then

11 = 6 + c ⇒ c = 11 - 6 = 5

y = 3x + 5 ← equation of linear function

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WHat are 3 possible solutions for this inequality 2/3(6x-3)>6
Ipatiy [6.2K]

Answer:

Step-by-step explanation:

2/3(6x-3)>6

4x-2>6

4x>8

x>2

Anything more than 2, so 3,4,5, etc

5 0
2 years ago
Find the sum of ∠BCD and ∠SBT in terms of x.
AleksAgata [21]
Let's\ \angle TCB=y^o\\\\\angle SBT\ is\ the\ exterior\ angle\ of\ \Delta TCB,\ therefore\ |\angle SBT|=x^o+y^o.\\\\|\angle\ BCD|\ +\ y^o=180^o-angles\ on\ one\ side\ of\ a\ straight\ line\\\\|\angle BCD|=180^o-y^o\\\\therefor\\\\\angle SBT+\angle BCD=x^o+y^o+180^o-y^o=x^o+180^o\\\\\boxed{Answer:\angle SBT+\angle BCD=x^o+180^o}
4 0
3 years ago
Read 2 more answers
1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)
Sveta_85 [38]

Answer:

1. -5x+3y+44=0

2. 2x+y-2=0

3. 2x+y-4=0

Step-by-step explanation:

Standard form of a line is Ax+By+C=0.

If a line passing through two points then the equation of line is

y-y_1=m(x-x_1)

where, m is slope, i.e.,m=\dfrac{y_2-y_1}{x_2-x_1}.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)

y+3=\dfrac{-5}{-3}(x-7)

y+3=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

-5x+3y+9+35=0

-5x+3y+44=0

Therefore, the required equation is -5x+3y+44=0.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to 2 x + y =-5.

Slope of the line : m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

y-2=-2(x-0)

y-2=-2x

2x+y-2=0

Therefore, the required equation is 2x+y-2=0.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y =-5.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

y-0=-2(x-2)

y=-2x+4

2x+y-4=0

Therefore, the required equation is 2x+y-4=0.

5 0
3 years ago
The waiting time at an elevator is uniformly distributed between 30 and 200 seconds. what is the probability a rider must wait m
stira [4]
1.5 minutes = 90 second

The probability density function is

f_X(x)=\begin{cases}\dfrac1{200-30}=\dfrac1{170}&\text{for }30\le x\le200\\\\0&\text{otherwise}\end{cases}

so the probability of interest is

\mathbb P(X>90)=\displaystyle\int_{90}^\infty f_X(x)\,\mathrm dx
\mathbb P(X>90)=\dfrac1{170}\displaystyle\int_{90}^{200}\mathrm dx
\mathbb P(X>90)=\dfrac{200-90}{170}=\dfrac{11}{17}\approx0.6471
5 0
3 years ago
1-10 just the answer not a really big explanation please
goblinko [34]

Answer:

Step-by-step explanation:

1) Isosceles triangle

2) Right angled triangle

3) Scalene triangle

4) Equilateral triangle

5) Right angled triangle

6) Scalene triangle

7) Equilateral triangle

8) Scalene triangle

9) a) Equilateral triangle

9) b) Scalene triangle

9) c)  Isosceles triangle

9) d) Right angled triangle

Note: Right angled triangle - If one angle is right angle, then it is Right angled triangle

Isosceles triangle: If two angles or two sides are equal, then it is Isosceles triangle.

Scalene triangle: If all three sides or three angles have different measurement, then it is Scalene triangle.

Equilateral triangle: If all the three sides are equal or all the three angles are equal, then it is Equilateral triangle

7 0
3 years ago
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