here i hope this answer will help you
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
1/3x - 2 = 1/4x + 11....it looks to me like one y was subbed in for another...
ur 2 equations are :
y = 1/3x - 2 and y = 1/4x + 11...but we need them in standard form...
y = 1/3x - 2
-1/3x + y = -2 ..multiply by 3
-x + 3y = -6.....or 3y - x = -6 <==
y = 1/4x + 11
-1/4x + y = 11 ...multiply by 4
-x + 4y = 44 or 4y - x = 44 <==
Answer:
Step-by-step explanation:
The average is 81 a low B, but if you throw out the low score it rises to 88.8, a high B.
I would use the median 88, 89 since it is higher and is a more accurate representation of the majority of the class
Answer:
Just a bored teen willing to help,
hope you're having a splendiferous day...
Step-by-step explanation:
Sasha: 16.8 seconds÷12 m=1.4 meter per second.
Sam: 46.5 seconds÷31 m=1.5 meter per second.
Sasha walked the fastest.
