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WINSTONCH [101]
4 years ago
11

A solid figure has a length of 4 inches and a width of 6 inches. The product of the length times the height is 12 square inches.

What is the volume of the solid figure, in cubic inches?
Mathematics
2 answers:
Alika [10]4 years ago
8 0
The volume of the solid figure is 72
Musya8 [376]4 years ago
6 0
Volume of the solid figure=
l×w×h where l represent length, w represent width, h represent height

We know that the product of the length times the width equal 12 square inches,so
l×h=12,and we know that the length is 4 inches

4×h=12
Divided 4 for both side
h=3 inches

V=l×w×h
V=4×3×6
V=72 square inches. As a result, the volume of the solid figure is 72 square inches. Hope it help!
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Answer:

a)  See attachment 1.

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c)  See attachment 2.

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Step-by-step explanation:

<h3><u>Part (a)</u></h3>

See attachment 1.  The line of best fit is shown in red.

<h3><u>Part (b)</u></h3>

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

<h3><u>Part (c)</u></h3>

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\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

<h3><u>Part (d)</u></h3>

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0).  Therefore, use these two points to find the slope of the line:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2

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\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2

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\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)

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