Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5


We are supposed to find he probability that the average score of the 49 golfers exceeded 62.
Formula : 


Refer the z table for p value
p value = 0.6103
P(x>62)=1-P(x<62)=1-0.6103=0.3897
Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897

solve for "K", to see what "K" is, or the "constant of variation",
once you found K, plug it back in y=Kx, and that's the equation
Answer:
NP= 9
Step-by-step explanation:
MP = 15
MN = 6
Let NP be x
MN+NP=MP
6+x=15
x=15-6
x=9
The value of NP is 9
First, make an equation.
y=4/5x-95
The first shift makes 1000 CD players, while the second shift makes 705 CD players.