(x^1/2 y^-2/3)^-6
= x^(1/2*-6) y^[(-2/3) *(-6)]
= x^-3 y ^4
= y^4 / x^3
answer is D. y^4 / x^3
Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
Answer:
140
Step-by-step explanation:
10/8 = 1.25
1.25 * 112 = 140
Answer:
AB = 6, BC = 6
AB = 4, AC = 4√2
BC = 2√2, AC = 4
Step-by-step explanation:
The sides of an isosceles right triangle are in the ratio 1:1:√2 where √2 is the hypotenuse.
So if, for example, BC = 2√2, then AC = 2√2 * √2 = 4.
