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3 years ago

What are the multipules of 3?

2 answers:

8 0

3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99,102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,147

Radda [10]3 years ago

7 0

3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90

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At a school carnival, three students spend an average of $10. Six other students spend an average of $4. What is the average amo

user100 [1]

$54 (if 10 for each of the 3 students and 4 dollars each of the 6 students)
$14 if not

6 0

3 years ago

plz explain why! Will be marked BRAINLIEST

wlad13 [49]

ANSWER

Eva is correct because 13/2 + 3/2 = 8

There is no mistake. Dakota may have thought that there was a mistake because Eva simplified when she got the answer for 4x which is correct but Dakota may have thought that it was incorrect.

6 0

3 years ago

Read 2 more answers

Factor: 6x^2 + 11x + 3 Write each factor in standard form.

yKpoI14uk [10]

The answer is: (2x+3) (3x+1)

8 0

3 years ago

Solve the proportion 4/x=8/(x-3)

jenyasd209 [6]

Answer:

x=-3

Step-by-step explanation:

4/x=8/(x-3)

We can solve this using cross products

4 ( x-3) = 8x

Distribute

4x -12 = 8x

Subtract 4x from each side

4x-4x-12 = 8x-12-4x

-12 =4x

Divide each side by 4

-12/4 = 4x/4

-3 =x

4 0

3 years ago

Read 2 more answers

Philip made a total of 9 bracelets and necklaces from 120 inches of cord. He used 8 inches of cord for each bracelet and 20 inch

Viktor [21]

Answer:

So Philip made 5 bracelets and 4 necklaces.

Step-by-step explanation:

Let x = number of bracelets and y = number of necklaces.

Since we have a total of 9 bracelets and necklaces,

x + y = 9 (1)

Also, we have 8 inches of cord for each bracelet and 20 inches of cord for each necklace, then the total length for the bracelet is 8x and that for the necklace is 20y.

So, the total length for both is 8x + 20y. Since the total length of cord used is 120 inches,

8x + 20y = 120 (2)

Simplifying it we have

2x + 5y = 30 (3).

Writing equations (1) and (3) in matrix form, we have

$\left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}9\\30\end{array}\right]$

Using Cramer's rule to solve for x and y,

$x = det \left[\begin{array}{ccc}9&1\\30&5\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

x = (9 × 5 - 30 × 1) ÷ (1 × 5 - 1 × 2)

x = (45 - 30) ÷ (5 - 2)

x = 15 ÷ 3

x = 5

$y = det \left[\begin{array}{ccc}1&9\\2&30\end{array}\right] /det \left[\begin{array}{ccc}1&1\\2&5\end{array}\right] \\$

y = (30 × 1 - 9 × 2) ÷ (1 × 5 - 1 × 2)

y = (30 - 18) ÷ (5 - 2)

y = 12 ÷ 3

y = 4

So Philip made 5 bracelets and 4 necklaces.

3 0

3 years ago