Question

Find the sum of the first 33 terms of the following series, to the nearest

Answer 1

Answer:

3234

Step-by-step explanation:

The series is arithmetic with a common difference = d = 6

First we need to find the 33rd term.  Use the formula $a_{n} = a_{1} + (n - 1)d$ where n = 33 and $a_{1} = 2$

$a_{33} = 2 + (33 - 1)6 = 2 + 32(6) = 194$

Now the formula for the sum of an arithmetic series is $S_{n} = \frac{n(a_{1} + a_{n} )}{2}$

So, $S_{33} = \frac{33(2 + 194)}{2}$

          = $\frac{33(196)}{2}$

          = 3234