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4 years ago

Can someone please help me with 2???? I’m fr fr struggling

Mathematics

2 answers:

ycow [4]4 years ago

5 0

Opposite sides are equal
.. VR = TS
.. y = x +11

.. VT = RS
.. y -3x = x +2

You can use the first equation to subsitute for y in the second equation.
.. x +11 -3x = x +2
.. 9 = 3x . . . . . . . . . . add 2x -2
.. 3 = x . . . . . . . . . . . divide by 3
.. y = 3 +11 = 14 . . . . substitute for x in the equation for y

The value of x is 3.
The value of y is 14.

Serggg [28]4 years ago

3 0

Answer:

i probably answer way to late but nope 352 262 3687

Step-by-step explanation:

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The game. Their scores are shoun below.

Harrizon [31]

Answer:

Barb is correct she won by 10 points

Darius's=480

Barb=490

5 0

3 years ago

A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec

natali 33 [55]

Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

50 parts means that $N = 50$

4 defective means that $k = 4$

10 are chosen, which means that $n = 10$

What is the probability this shipment passes inspection?

Probability that none is defective, so:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968$

0.3968 = 39.68% probability this shipment passes inspection.

6 0

3 years ago

Absolute value inequalities. 10-4|9y-10|<-94

Ivahew [28]

Answer: $\begin{bmatrix}\mathrm{Solution:}\:&\:y4\:\\ \:\mathrm{Decimal:}&\:y4\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:-\frac{16}{9}\right)\cup \left(4,\:\infty \:\right)\end{bmatrix}$