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AURORKA [14]
3 years ago
7

Can someone please help me with 2???? I’m fr fr struggling

Mathematics
2 answers:
ycow [4]3 years ago
5 0
Opposite sides are equal
.. VR = TS
.. y = x +11

.. VT = RS
.. y -3x = x +2

You can use the first equation to subsitute for y in the second equation.
.. x +11 -3x = x +2
.. 9 = 3x . . . . . . . . . . add 2x -2
.. 3 = x . . . . . . . . . . . divide by 3
.. y = 3 +11 = 14 . . . . substitute for x in the equation for y

The value of x is 3.
The value of y is 14.
Serggg [28]3 years ago
3 0

Answer:

i probably answer way to late but nope 352 262 3687

Step-by-step explanation:

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In the equation y=x-9 the variable to y is the ?
LenKa [72]

Answer:

-9

Step-by-step explanation:

This equation is written in slope-intercept form. <em>-9 </em>represents the y-intercept, and <em>x </em>represents the slope, which is positive one over one.

7 0
2 years ago
Andrew bought a house worth 200,000 dollars the house value appreciates 1% per year which of the following would help you find t
Aleks [24]

Answer: Option 1:

y=200,000(1.01)exponent 20

Step-by-step explanation:

The house value appreciates 1% per year. It means that the rate at which it is appreciating is exponential. We would apply the formula for exponential growth which is expressed as

y = b(1 + r)^ t

Where

y represents the value of the house after t years.

t represents the number of years.

b represents the initial value of the house.

r represents rate of growth.

From the information given,

b = 200,000 dollars

r = 1% = 1/100 = 0.01

t = 20 years

Therefore,

y = 200000(1 + 0.01)^20

y = 200000(1.01)^20

7 0
3 years ago
The focal lengths of the objective lens and the eyepiece of a microscope are 0.50 cm and 2.0 cm, respectively, and their separat
VladimirAG [237]

Answer:

- 103.7

Step-by-step explanation:

Given:

Focal length of the eyepiece, f = 2.0 cm

Focal length of the objective lens, f' = 0.50 cm

Separation for minimum eyestrain = 6,0 cm

Image distance, v = - 25 cm

Now, from the lens formula,

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

here, u is the object distance

on substituting the respective values, we get

\frac{1}{2}=\frac{1}{u}+\frac{1}{-25}

or

u = 1.852 cm

also, the separation is adjusted for minimum eyestrain,

therefore, image distance for the objective lens, v' = 6 - 1.852 = 4.148 cm

Now, for the objective lens

using the lens formula, we get

\frac{1}{0.5}=\frac{1}{u'}+\frac{1}{4.418}

Here, u' is the distance between the physical object and objective lens

or

u' = 0.568 cm

Thus,

Magnification, m = -\frac{vv'}{ff'}

or

m =-\frac{25\times4.418}{0.5\times2}

or

m = - 103.7

4 0
2 years ago
How to prove two triangles congruent
dezoksy [38]
There's a lot of theorems SAS, ASA, SSA, AAS, SSS

S=Side
A=Angle

If the order of the sides and angles in one of the above are congruent, then the triangles are congruent.

Hope this helps :D
7 0
3 years ago
Read 2 more answers
–4(5² – 3) +6² I need help solving that​
Marat540 [252]

Answer:

-52

Have a great day! Brainliest?

4 0
2 years ago
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