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1 answer:
Tan3A=tan(2A+A)
We know that , tan(x+y)=(tanx + tany)/(1 - (tanx)(tany))
tan(2A+A)=(tan2A+tanA)/(1 - (tan2A)(tanA))— (1)
We know that , tan2x=2tanx/(1 - tan^2x)
So, by substituting tan2A in (1),we get,
=[2tanA/(1 - tan^2A) + tanA]/1- (2tanA/(1 - tan^2A))(tanA)]
=[2tanA+tanA - tan^3A]/[1 - tan^2A - 2tan^2A]
=[3tanA - tan^3A]/[1-3tan^2A]
Therefore, tan3A= [3tanA - tan^3A]/[1-3tan^2A]
We know that , tan(x+y)=(tanx + tany)/(1 - (tanx)(tany))
tan(2A+A)=(tan2A+tanA)/(1 - (tan2A)(tanA))— (1)
We know that , tan2x=2tanx/(1 - tan^2x)
So, by substituting tan2A in (1),we get,
=[2tanA/(1 - tan^2A) + tanA]/1- (2tanA/(1 - tan^2A))(tanA)]
=[2tanA+tanA - tan^3A]/[1 - tan^2A - 2tan^2A]
=[3tanA - tan^3A]/[1-3tan^2A]
Therefore, tan3A= [3tanA - tan^3A]/[1-3tan^2A]
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Answer:
The height of the larger traffic signs is 51.96 inches
Step-by-step explanation:
Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches
Now, A company makes similar traffic signs of perimeter 1.25 of original
New perimeter will be 1.25x144=180 inches
Let triangle ABC be a larger triangle with 180inches of the perimeter.
It is given that the triangle is an equilateral triangle,
Therefore, Side AB=BC=AC
The perimeter of a triangle ABC is
AB+BC+AC=180
3AB=180
AB=60 inches
Figure show that triangle ABC and AD is the height of the triangle.
Since, the triangle ABC is an equilateral triangle,
AD is the perpendicular bisector of BC
so that,
BD=DC and Angle ADB=90
In right triangle ADB,
Angle D =90 and Angle B =60
Side BD=60/2=30 inches and AB=60 inches
Using Pythagoras theorem,
AD=51.96 inches
Thus, The height of the larger traffic signs is 51.96 inches
