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denis23 [38]
2 years ago
15

Help mi plzz.........​

Mathematics
1 answer:
faust18 [17]2 years ago
3 0
Tan3A=tan(2A+A)

We know that , tan(x+y)=(tanx + tany)/(1 - (tanx)(tany))

tan(2A+A)=(tan2A+tanA)/(1 - (tan2A)(tanA))— (1)

We know that , tan2x=2tanx/(1 - tan^2x)

So, by substituting tan2A in (1),we get,

=[2tanA/(1 - tan^2A) + tanA]/1- (2tanA/(1 - tan^2A))(tanA)]

=[2tanA+tanA - tan^3A]/[1 - tan^2A - 2tan^2A]

=[3tanA - tan^3A]/[1-3tan^2A]

Therefore, tan3A= [3tanA - tan^3A]/[1-3tan^2A]

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A gift box is in the shape of a trapezoidal prism with base lengths of 7 inches and 5 inches and a height of 4 inches. The heigh
jek_recluse [69]
First of all there are multiple formula's to get the volume of a trapezoidal prism:

V=(1/2 * (base1 + base2) * h) * height prism

Using the numbers you gave: 
base1 = 7     base2 = 5     h = 4     height prism = 8

Putting this into the equation:  V=(1/2 * (7 <span>+ 5) * 4) * 8
V= (1/2 * 12 * 4) * 8
V = 24 * 8
V = 192

The volume of the gift box is 191 inches squared.</span>
6 0
3 years ago
SOMEBODY HELP MEEE!!!!
VladimirAG [237]
Solution= x=5
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8 0
2 years ago
Y=1/2x+2 y=1/3x+2 solve for graphing ​
madreJ [45]

Answer:

I plotted it out on the graph and here it is:

6 0
1 year ago
Two boats started to move towards each other from two docks, located 30 miles apart. One boat moved at a speed of 3 miles per ho
blagie [28]

Answer:

3.333 hours

Step-by-step explanation:

Given the total distance is 30 miles, and boat 1 travels at 3 mph and boat 2 travels at 6 mph, and the time for both is the same. Distance is speed S times time T so

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30 = (S1 * T) + (S2 * T)

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5 0
3 years ago
Given ZW=20. Answer the questions please. ​
djyliett [7]

a) Corresponding angles of similar figures are congruent, so \angle B \cong \boxed{\angle Z}

b) Scale factor = (image)/(preimage). Since we are looking for ABCD to WZYX, this means that WZYX is the image and ABCD is the preimage. Thus, the scale factor is \frac{25}{10}=\boxed{5/2}

c) Since the scale factor is 5/2,

\frac{20}{t}=\frac{5}[2}\\\\40=5t\\ \\ t=\boxed{8}

8 0
2 years ago
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