Answer:
They are not independent
Step-by-step explanation:
Given
E = Occurrence of 1 on first die
F = Sum of the uppermost occurrence in both die is 5
Required
Are E and F independent
First, we need to list the sample space of a roll of a die

Next, we list out the sample space of F


In (1): the sample space of E is:

So:


In (2): the sample space of F is:

So:



For E and F to be independent:

Substitute values for P(E) and P(F)
This gives:


However, the actual value of P(E and F) is 0.
This is so because
and
have 0 common elements:
So:

Compare
and
.
These values are not equal.
Hence: the two events are not independent
Answer:
Write the expression as:"
70
+ 2
* 2
− 18a " ;
______________________________________________________or; write as:
______________________________________________________ "
70.32 + (2.1) * (2.7) − 18a " ;
______________________________________________________To simplify:
______________________________________________________ Using "PEDMAS" (the "order of operations") ;
the "multiplication" comes first;
So: → "(2.1) * (2.7) = 5.67 " .
And rewrite:
______________________________________________________ " 70.32 + 5.67 − 18a " .
Now: " 70.32 + 5.67 = 75.99 " ;
So, we can the final simplified expression as:
______________________________________________________ "
75.99 − 18a " ;
or; write as: "
75
− 18a " .
______________________________________________________
Answer:
68% of jazz CDs play between 45 and 59 minutes.
Step-by-step explanation:
<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?
Let X = <u>playing time of jazz CDs</u>
SO, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
Now, according to the 68-95-99.7 rule, it is stated that;
- 68% of the data values lie within one standard deviation points from the mean.
- 95% of the data values lie within two standard deviation points from the mean.
- 99.7% of the data values lie within three standard deviation points from the mean.
Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;
For 45 minutes, z-score is =
= -1
For 59 minutes, z-score is =
= 1
This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.
Answer:
1. .466-
2. -0.6
3. .466-
4. .466-
5. 0.6
Step-by-step explanation:
I gotchu! there is no association shown between the two in this sample because the given information only shows the correlation between fur color and environmental and NOT gender.
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