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adelina 88 [10]
3 years ago
12

How to find the LCM OF two numbers

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0
You list the multiples of both numbers and see which number they share that is on each table For example, 3,6,9,(12),15,18,21,(24) 4,8,(12),16,20,(24) 12 is the least common multiple of the numbers 3 and 4
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What is the formula for the nth term of the given sequence 100, 20, 4, …
Naily [24]

Answer:

a_n=100 \left(\dfrac15\right)^{n-1}

Step-by-step explanation:

General equation of geometric sequence:  a_n=ar^{n-1}

Given:

  • a₁ = 100
  • a₂ = 20
  • a₃ = 4

\implies a_1=a=100

\implies a_2=100 \cdot r=20

\implies a_3=100 \cdot r^2=4

Common ratio:

r=\dfrac{a_3}{a_2}=\dfrac{4}{20}=\dfrac15

Therefore:

a_n=100 \left(\dfrac15\right)^{n-1}

6 0
1 year ago
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lukranit [14]
To the first question it would be a because all of the brown spots look like an equal in size equation be with number two because according to the ox
7 0
3 years ago
Which accurately describes a circle with a radius 12 centimeters and center Q?
JulijaS [17]

Answer:

the answer is d!

Step-by-step explanation:

because the radius is measuring the distance from any point on the circle to the very center of the circle

5 0
3 years ago
Need help.<br> Picture has it all..<br> Correct answers only please.
Serggg [28]
Tan x degrees = 31

To find X use arctan.

x = arctan(31)

x = 88.15

x = 88.2 (rounded to the nearest tenth)
7 0
2 years ago
A conjecture and the flowchart proof used to prove the conjecture are shown.
viva [34]

The required proof of parallelogram is given below,

What is parallelogram?

A parallelogram is a straightforward quadrilateral with two sets of parallel sides in Euclidean geometry. The opposing or confronting sides and the opposing angles in a parallelogram are of equal length.

For a parallelogram, opposite sides are always equal and parallel.
So for the given parallelogram, we get AD = BC and AD and BC are parallel.

AD and BC is parallel and DC is common side, therefore, \angle 1 = \angle 3 ......(1)

Given \angle 3 = \angle 2  .......(2)

Therefore, from condition (1) and (2), we get

\angle 1 = \angle 2

If \angle 1 = \angle 2 then DC bisects the angle \angle ADE. [Proved]

To learn more about parallelogram from the given link

brainly.com/question/970600

#SPJ1

4 0
1 year ago
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