The value of P(4, 6) when the two number cubes are tossed is 1/36
<h3>How to determine the probability?</h3>
On each number cube, we have:
Sample space = {1, 2, 3, 4, 5, 6}
The individual probabilities are then represented as:
P(4) =1/6
P(6) =1/6
The value of P(4, 6) when the two number cubes are tossed is:
P(4, 6) = P(4) * P(6)
This gives
P(4, 6) = 1/6 * 1/6
Evaluate
P(4, 6) = 1/36
Hence, the value of P(4, 6) when the two number cubes are tossed is 1/36
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Answer:
The probability is 0.0428
Step-by-step explanation:
First, let's remember that the binomial distribution is given by the formula:
where k is the number of successes in n trials and p is the probability of success.
However, the problem tells us that when there isn't a number of trials fixed, we can use the geometric distribution and the formula for getting the first success on the xth trial becomes:

The problem asks us to find the probability of the first success on the 4th trial (given that the first subject to be a universal blood donor will be the fourth person selected)
Using this formula with the parameters given, we have:
p = 0.05
x = 4
Substituting these parameters in the formula and solving it, we get:

Therefore, the probability that the first subject to be a universal blood donor is the fourth person selected is 0.0428 or 4.28%
Answer:
18
Step-by-step explanation:
x² = 16² + 30² - 2(16)(30)cos 30°
x² = 256 + 900 - 960(0.866)
x² = 1156 - 831.36
x² = 324.64
x = 18.02
Approx. 18
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