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Vera_Pavlovna [14]
3 years ago
7

Do y'all understand this? please help me​

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

( -3.5, 1.5 )

Step-by-step explanation:

You have to use slope-intercept form to solve this; y=mx+b

m= 7/2 (x,y) = (-3,3)

3 = 7/2 (-3) + b

3 = 10.5 + b

b = -7.5

y = 7/2 - 7.5

The coordinates would be ( -3.5, 1.5 )

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A tank having length, breadth and height 10 m, 9 m
Ne4ueva [31]

Answer:

length times width times height

Step-by-step explanation:

width is height by the way

so 20×10×9 gives you 1800

1800 petrol can hold on Meters

7 0
3 years ago
Choose the correct answer to 1,889/36.<br> 42 R17<br> 51 R53<br> 52 R15<br> 52 R17
ozzi

Answer:

52 R17

Step-by-step explanation:

52 * 36 = 1872

1889 - 1872 = 17

--> 52 R17

3 0
3 years ago
Read 2 more answers
Veronica has been saving dimes and quarters. She has 94 coins in all and the total value is $19.30. How many dimes and how many
Stolb23 [73]

Answer:

Step-by-step explanation:

d + q = 94.....d = 94 - q

0.10d + 0.25q = 19.30

0.10(94 - q) + 0.25q = 19.30

9.4 - 0.10q + 0.25q = 19.30

-0.10q + 0.25q = 19.30 - 9.40

0.15q = 9.90

q = 9.90/0.15

q = 66 <===== there are 66 quarters

d + q = 94

d + 66 = 94

d = 94 - 66

d = 28 <==== there are 28 dimes

3 0
3 years ago
Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
Help or else i’ll fail
Georgia [21]
The answer is equilateral
8 0
3 years ago
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