Answer:
-14 + x\4 + x
Step-by-step explanation:
Start by plugging the g(x) function into the f(x) for every "x" you see, then take THAT answer and plug into the h(x) function for that "x" you see. You will arrive at the above answer.
Answer:
Option C.
Step-by-step explanation:
Note: x is missing in the second equation.
The given equations are
It can we written as
![\left[\left.\begin{matrix}4 & -7\\ -2 & 6\end{matrix}\right|\begin{matrix}-12\\ 11\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D4%20%26%20-7%5C%5C%20-2%20%26%206%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-12%5C%5C%2011%5Cend%7Bmatrix%7D%5Cright%5D)
Divide row 1 be 4.
![\left[\left.\begin{matrix}1 & -\dfrac{7}{4}\\ -2 & 6\end{matrix}\right|\begin{matrix}-3\\ 11\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%20-%5Cdfrac%7B7%7D%7B4%7D%5C%5C%20-2%20%26%206%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-3%5C%5C%2011%5Cend%7Bmatrix%7D%5Cright%5D)
Applying 
, we get
![\left[\left.\begin{matrix}1 & -\dfrac{7}{4}\\ 0 & \dfrac{5}{2}\end{matrix}\right|\begin{matrix}-3\\ 5\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%20-%5Cdfrac%7B7%7D%7B4%7D%5C%5C%200%20%26%20%5Cdfrac%7B5%7D%7B2%7D%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-3%5C%5C%205%5Cend%7Bmatrix%7D%5Cright%5D)
Applying 
, we get
![\left[\left.\begin{matrix}1 & -\dfrac{7}{4}\\ 0 & 1\end{matrix}\right|\begin{matrix}-3\\ 2\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%20-%5Cdfrac%7B7%7D%7B4%7D%5C%5C%200%20%26%201%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D-3%5C%5C%202%5Cend%7Bmatrix%7D%5Cright%5D)
Applying 
, we get
![\left[\left.\begin{matrix}1 & 0\\ 0 & 1\end{matrix}\right|\begin{matrix}\dfrac{1}{2}\\ 2\end{matrix}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cleft.%5Cbegin%7Bmatrix%7D1%20%26%200%5C%5C%200%20%26%201%5Cend%7Bmatrix%7D%5Cright%7C%5Cbegin%7Bmatrix%7D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%202%5Cend%7Bmatrix%7D%5Cright%5D)
Since 
, therefore required ordered pair is 
.
Hence, option C is correct.
Answer:
No.
Step-by-step explanation:
Triangle DFE justifies itself with the SAS (side-angle-side) postulate, while Triangle ABC simply shows that ∡B & A are similar. They are not justified by the same standard, and so there is no way to tell if these triangles are similar.
Answer:
the answer is A for the shaded region
