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Bingel [31]
3 years ago
7

WILL GIVE BRAINLIEST! Find k so that (5, k) is equidistant from (–1, 2) and (3, 0).

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

9

Step-by-step explanation:

So first I created 2 distance forumlas and set them equal to each other

\sqrt{(5+1)^2+(k-2)^2} =\sqrt{(5-3)^2+(k)^2}

then I simplified them

(5+1)^2+(k-2)^2 =(5-3)^2+(k)^2\\

36 + k^2 - 4k +4 = k^2 + 4

-4k + 36 = 0\\

4k = 36

k = 9

when k = 9, the two distances are equal

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Complete the point-slope equation of the line through (-1,6)(−1,6)left parenthesis, minus, 1, comma, 6, right parenthesis and (1
velikii [3]

Answer:

y-6 = -\frac{1}{2} (x+1)

Step-by-step explanation:

For this case we have two points given (-1,6) and (1,5)

And we want to complete the point slope equation of the line:

y-6 = m(x-x_o)

We need to find the slope and we can use the following formula:

m = \frac{y_2 -y_1}{x_2 -x_1}

And replacing the info we got:

m= \frac{5-6}{1-(-1)}=-\frac{1}{2}

And then the equation would be given by:

y-6 = -\frac{1}{2} (x- (-1))

And our final answer would be:

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3 0
3 years ago
Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su
Marysya12 [62]

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%

Hence, there are 88% chances that one or the other but not both of the units will be successful.

6 0
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