Question

WILL GIVE BRAINLIEST! Find k so that (5, k) is equidistant from (–1, 2) and (3, 0).

Answer 1

Answer:

9

Step-by-step explanation:

So first I created 2 distance forumlas and set them equal to each other

$\sqrt{(5+1)^2+(k-2)^2} =\sqrt{(5-3)^2+(k)^2}$

then I simplified them

$(5+1)^2+(k-2)^2 =(5-3)^2+(k)^2$

$36 + k^2 - 4k +4 = k^2 + 4$

$-4k + 36 = 0$

$4k = 36$

$k = 9$

when k = 9, the two distances are equal