st + 3t = 6 for s
Subtract 3t to both sides
st + 3t - 3t = 6 - 3t
Simplify
st = 6 - 3t
Divide both sides by t
st/t = (6-3t)/3
simplify
s = 6/3 - 3t/3
s = 2 - t
Answer: $ 2.55
Step-by-step explanation:
Answer:
Step-by-step explanation:
10000*4%= 400 Geese year1
10400*4%=416 Geese year 2
10816*4%= 432.64 Geese year 3
11,248.64*4%= 449.95 Geese. year 4
11248.64+449.95= 11698.59
11698.59-10000=1698.59
Increased by 1699 Geese.
Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒

Equation [2] ⇒

We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;

and

, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either

or

the subject:


Then we substitute

into Equation [2]






Now we know the value of

which is

, substitute this value into

we have

Answer:
Numbers of books = 13
Numbers of CDs = 7