<span>Using processing software (Excel) or even a decent scientific calculator. You input the values and generate the best fit cubic equation.
For number 1, the equation is
y = 8x10</span>⁻⁵ x³ - 0.0097 x² + 0.374 x + 1.083
where x is the number of years since 1900
y is the pounds cheese consumed
For number 2, the equation is
y = -3x10⁻⁵ x³ + 0.0028 x² + 0.2155 x + 1.7736
For number 3
P(-1) = 18
Answer: He has 7 at the moment, technically, if he still has the bag, he still has all 36
Step-by-step explanation:
The answer for x is x=6 sorry if I’m wrong
Answer:
let
hypotenuse[h]=60ft
base[b]=36ft
perpendicular [p]=48ft
by using Pythagoras law
p²+b²=h²
48²+36²=60²
2896≠3600
since p²+b²≠ h²[<u>so</u><u> </u><u>the</u><u> </u><u>stage</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>in</u><u> </u><u>a</u><u> </u><u>right</u><u> </u><u>angled</u><u> </u><u>tria</u><u>ngle</u><u>]</u><u>but</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>scalene</u><u> </u><u>triangle</u>
Answer:
The amount at the end of second quarter is $1842.704
Step-by-step explanation:
Given as :
The principal in saving account = $1640
The rate of interest = 6 % compounded quarterly
The time period = 6 months
Now,<u> from compounded method</u>
The amount at the end of first quarter =
= principal + 6 % of principal
I.e
= $1640 + 6 % × $1640
Or,
= $1640 + $ 98.4
∴
= $1738.4
Again ,
The amount at the end of second quarter =
=
+ 6 % of
I.e
= $1738.4 + 6 % × $1738.4
Or,
= $1738.4 + $104.304
∴
= $1842.704
So, The amount at the end of second quarter =
= $1842.704
Hence , The amount at the end of second quarter is $1842.704 Answer