Answer:
Natural/Counting Numbers
Step-by-step explanation:
It is the smallest subset a number can classify into. It is all of the numbers from 1 to positive infinity.
False...garnishment is when they deduct money directly out of ur account
Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
Answer:
D. 54
Step-by-step explanation:
Right angle = 90°
3/5 of 90°
3/5 × 90°
270 ÷ 5 = 54°
Answer:
Step-by-step explanation:
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