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3 years ago

Write the polynomial function with the given zeros. 5. x= -1,-1, 6

Mathematics

1 answer:

Allushta [10]3 years ago

5 0

Answer:

Step-by-step explanation:

There are many such polynomials, but the one with leading coefficient of 1 is

y = (x+1)(x-1)(x-6) = x^3 - 6x^2 - x + 6

Not sure what you want to do with the 5, If that is the y-intercept, then since

(1)(-1)(-6) = 6, we will need

y = 5/6 (x^3 - 6x^2 - x + 6)

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X + 5 ≤ 13 what's the answer for this question?

wariber [46]

Answer:

Inequality Form: x ≤ 8

Interval Notation: (-∞,8]

Step-by-step explanation:

x + 5 ≤ 13

Subtract 5 on both sides...

13 - 5 = 8

You're left with x ≤ 8

Inequality Form: x ≤ 8

Interval Notation: (-∞,8]

6 0

3 years ago

Among all the rectangles whose perimeters are 100 feet, find the dimensions of the one with the maximum area. explain step by st

kompoz [17]

We let x be the length and y be the width of the rectangle. Then,

Perimeter = 2x + 2y
100 = 2x + 2y
50 = x + y
y = 50 - x

Area = xy
A = x(50 - x)
A = 50x - x^2

We then take the derivative; set it equal to zero:

A ' = 50 - 2x
0 = 50 - 2x
2x = 50
x = 25
y = 50 - x
y = 50 - 25
y = 25

Therefore, the dimensions are 25 and 25.

7 0

2 years ago

C is equidistant from A and B. What is the value of x? A. 6 B. 8 C. 12 D. 14

VLD [36.1K]

The correct answer that i came up with is D

6 0

2 years ago

Find the distance between the points (0,2)and (-5,-9)The answer must be a whole number or a fully simplified radical expression

LiRa [457]

Answer:

d = $\sqrt{146}$

Step-by-step explanation:

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(-5-0)^2+(-9-2)^2}\\d= \sqrt{(-5)^2+(-11)^2}\\d= \sqrt{25+121}\\d= \sqrt{146}$

7 0

2 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Solution:

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

Read 2 more answers