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1 year ago

What is a problem that requires adding one two the quotient

Mathematics

1 answer:

Nikolay [14]1 year ago

6 0

division problem

In a division problem, the number being divided into pieces is the dividend. The number by which the dividend is divided is called the divisor. And the answer to the division problem is the quotient.

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Solve for x:<br> 1 1/5x−2 1/3<1/7x+1 1/2

Mashcka [7]

Answer: $x$

Step-by-step explanation:

$1\frac{1}{5}x-2\frac{1}{3}$

Add $2\frac{1}{3}$ on both sides and subtract $\frac{1}{7}x$ on both sides to leave x's on the left side and independent values on the right.

$(2\frac{1}{3}-\frac{1}{7}x) +1\frac{1}{5}x-2\frac{1}{3}$

$1\frac{1}{5}x-\frac{1}{7}x$

Solve the fractions.

$1(\frac{1}{5}-\frac{1}{7})x$

$1(\frac{(1)(7)-(5)(1)}{(5)(7)} )x$

$1(\frac{7-5}{35} )x$

$1(\frac{2}{35} )x$

$1\frac{2}{35}x$

Convert the mixed fraction $1\frac{2}{35}$ to an improper fraction. You can do this by multiplying 1 times 35 and adding 2.

$\frac{37}{35}x$

Now use the reciprocal (inverse fraction) and multiply on both sides to isolate x.

$(\frac{35}{37}) (\frac{37}{35})x$

$x$

5 0

2 years ago

Based on your observations, what conclusion can you draw about the lengths of AB DB AE EC

Deffense [45]

Answer:

The ratio of AD to DB is equal to the ratio of AE to EC. In other words, the pairs of lengths are proportional.

Step-by-step explanation:

Sample answer from plato

4 0

2 years ago

The population of Mexico has been increasing at an annual rate of 1.7%. If the population was 100,350,000 in the year 2000, pred

Svetllana [295]

We can withdraw a equation to give mexico population

P = M.(1 + i)^t

So,

First of all, how many years passed? 2015 - 2000 = 15. Our time is 15, our annual rate is 1,7%, time to calc.

P = 100350000.(1 + 1,7%)^15

1,7% = 0,017

P = 100350000.(1 + 0,017)^15

P = 100350000.(1,017)^15

P = 100350000.1,2876988084901218382866596204289

P = 129220575,43198372647206629291004

Rounding

P = 129,220,575

8 0

2 years ago

Read 2 more answers

Which number line represents the solution to [x-5]=1

alexandr402 [8]

Answer:

Step-by-step explanation:

If there are illustrations to given problems, please share those illustrations. Thank you.

The only value of x for which [x-5]=1 is true is 6: [6-5]=1

3 0

2 years ago

Read 2 more answers

QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is

soldi70 [24.7K]

Answer:

$PQR = 20$

Step-by-step explanation:

Given

Bisector: QS

$PQS = 5x$

$RQS = 2x + 6$

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

$PQS = RQS$

Substitute expressions for PQS and RQS

$5x = 2x + 6$

Collect Like Terms

$5x - 2x = 6$

$3x = 6$

Divide both sides by 3

$x = 2$

Solving for PQR;

$PQR = PQS + RQS$

$PQR = 5x + 2x + 6$

$PQR = 7x + 6$

Substitute 2 for x

$PQR = 7 * 2 + 6$

$PQR = 14 + 6$

$PQR = 20$

4 0

2 years ago