1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
o-na [289]
3 years ago
14

3(2b+4)=6(5b+2)please step by step

Mathematics
1 answer:
Lena [83]3 years ago
3 0
A b=0    Subtract 12 from both sides 6b+12-12=30b+12-12

You might be interested in
13)
Alenkasestr [34]

Answer:

22

Step-by-step explanation:

did the test with that question

6 0
3 years ago
Read 2 more answers
H(n) = 3^n+3; Find h (3n)
olya-2409 [2.1K]

Answer:

The option which you chose is absolutely right.

Step-by-step explanation:

h(n) = 3^ n + 3

h(3n) = 3 ^3n + 3

Hope it will help :)

5 0
3 years ago
Evaluate −m2n+m2 when m=−4.
fgiga [73]

Answer:

Does this answer your question − 16 n  +  16

4 0
3 years ago
Find the standard equation of a sphere that has diameter with the end points given below. (3,-2,4) (7,12,4)
DiKsa [7]

Answer:

The standard equation of the sphere is (x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

Step-by-step explanation:

From the question, the end point are (3,-2,4) and (7,12,4)

Since we know the end points of the diameter, we can determine the center (midpoint of the two end points) of the sphere.

The midpoint can be calculated thus

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Let the first endpoint be represented as (x_{1}, y_{1}, z_{1}) and the second endpoint be (x_{2}, y_{2}, z_{2}).

Hence,

Midpoint = (\frac{x_{1} + x_{2}  }{2}, \frac{y_{1} + y_{2} }{2}, \frac{z_{1} + z_{2}  }{2})

Midpoint = (\frac{3 + 7  }{2}, \frac{-2+12 }{2}, \frac{4 + 4  }{2})

Midpoint = (\frac{10 }{2}, \frac{10}{2}, \frac{8  }{2})\\

Midpoint = (5, 5, 4)

This is the center of the sphere.

Now, we will determine the distance (diameter) of the sphere

The distance is given by

d = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} + (z_{2}- z_{1})^{2}      }

d = \sqrt{(7 - 3)^{2} +(12 - -2)^{2} + (4- 4)^{2}

d = \sqrt{(4)^{2} +(14)^{2} + (0)^{2}

d = \sqrt{16 +196 + 0

d =\sqrt{212}

d = 2\sqrt{53}

This is the diameter

To find the radius, r

From Radius = \frac{Diameter}{2}

Radius = \frac{2\sqrt{53} }{2}

∴ Radius = \sqrt{53}

r = \sqrt{53}

Now, we can write the standard equation of the sphere since we know the center and the radius

Center of the sphere is (5, 5, 4)

Radius of the sphere is \sqrt{53}

The equation of a sphere of radius r and center (h,k,l) is given by

(x-h)^{2} + (y-k)^{2} + (z-l)^{2}  = r^{2}

Hence, the equation of the sphere of radius \sqrt{53} and center (5, 5, 4) is

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = \sqrt{(53} )^{2}

(x-5)^{2} + (y-5)^{2} + (z-4)^{2}  = 53

This is the standard equation of the sphere

6 0
3 years ago
A sandbox is being built in a park. The diagram shows the four vertices of the sandbox. Each unit in the
____ [38]

Answer:

the answer is 90 square feet.

Step-by-step explanation:

the length is 10, and the height is 9.

10×9=90

5 0
3 years ago
Other questions:
  • Find the measure of < AED for m < BEC = 96
    6·2 answers
  • What is the value of this expression when k=5? (3k)2 -10
    9·2 answers
  • A customer gives you a $100 bill for a purchase that totals $22.75. What is the best money combination to give the $77.25 to the
    11·2 answers
  • OMG HELP PLEASE!!!!!!!!!!
    13·2 answers
  • Find the distance between<br> (-1, - 3) and (8, – 3).
    13·1 answer
  • Some plz help meeeeeeeeeeereee I really neeeeeeeeeddddddddd ittttttttttt
    6·1 answer
  • 3. Retaj is cutting a roll of string into pieces that are each 2/3 m long . If the yarn is 6 m long, how many pieces of yarn did
    5·1 answer
  • Can somebody solve this PLZ PLZ PLZ!
    14·2 answers
  • Plzzzzzzzzzzzz help me
    6·1 answer
  • You want the billboard to have an area of 144 ft. 1. What do you know about the height and the width of the billboard?​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!