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o-na [289]
3 years ago
14

3(2b+4)=6(5b+2)please step by step

Mathematics
1 answer:
Lena [83]3 years ago
3 0
A b=0    Subtract 12 from both sides 6b+12-12=30b+12-12

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I need help with this question please
Gemiola [76]

Answer:

X = 13

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the value of x such that 365 based seven + 43 based x = 217 based 10.
Pepsi [2]

We need to find the base x in the following equation:

365_7+43_x=217_{10}

First, lets convert 365 from base 7 to base 10. This is given by

365_7=3\times7^2+6\times7^1+5\times7^0

where the upperindex denotes the position of eah number. This gives

\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

43_x=4\times x^1+3\times x^0

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

43_x=(4x+3)_{10}

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

194_{10}+(4x+3)_{10}=217_{10}

For simplicity, we can omit the 10 and get

194+4x+3=217

so, we can solve this equation for x. By combining similar terms. we have

197+4x=217

and by moving 197 to the right hand side, we obtain

\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}

Finally, we get

\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}

Therefore, the solution is x=5

8 0
1 year ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
What is 8.3x10^-9 in standard form?
wariber [46]
.0000000083


( eight zeros.)
6 0
3 years ago
Alberta is going to take a 2-hour-26-minute flight from Chicago, Illinois, to
BigorU [14]

Answer: 1:15pm

Step-by-step explanation:

8 0
2 years ago
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