1 = 4
-4an - 1
-4an -(4)
an 1
The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
<h3>How to determine the intersection of the lines?</h3>
The lines are given as:
y = -14x + 3 and y = -32x+3
Substitute y = -32x+3 in
-32x+3 = -14x + 3
Evaluate the like terms
-18x = 0
Divide by -18
x = 0
Substitute x = 0 in y = -14x + 3
y = -14(0) + 3
Evaluate
y = 3
Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
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x equals negative 8 and negative 4
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