the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer:
yes this is correct
Step-by-step explanation:
Answer:
1/24
Step-by-step explanation:
We can't subtract two fractions with different denominators. So you need to get a common denominator. To do this, you'll multiply the denominators times each other... but the numerators have to change, too. They get multiplied by the other term's denominator.
So we multiply 11 by 8, and get 88.Then we multiply 7 by 12, and get 84.
Next we give both terms new denominators -- 12 × 8 = 96.
So now our fractions look like this:
88
/96
-84
/96
Step 2
Since our denominators match, we can subtract the numerators.
88 − 84 = 4
So the answer is:
4
/96
Step 3
Last of all, we need to simplify the fraction, if possible. Can it be reduced to a simpler fraction?
To find out, we try dividing it by 2...
Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
4
/96
÷ 2 =2
/48
Let's try dividing by 2 again...
Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
2
/48
÷ 2 =1
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Let's try dividing by 2 again...
No good. 2 is larger than 1. So we're done reducing. There you have it! The final answer is:
11
/12
-7
/8=1
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