Answer:
Step-by-step explanation:
3 different china dinner sets, each consisting of 5 plates consist of 15 plates.
A customer can select 2 plates in
different ways.
2 plates can be selected from the same dinner set in
different ways.
Thus, the probability that the 2 plates selected will be from the same dinner set is
The order of the persons seated in front is not important so long as there are four of them. The combination of the given problem is expressed as,
6C4
The numerical value of the combination is 15. Thus, the answer to this item is letter D.
1.155 is the x, and the hypotenuse is 2.309
Answer:
<h2>
x=25</h2>
Step-by-step explanation:
Hope this helps!
<h2><em>
:)</em></h2>
