Step-by-step explanation:
Given that,
Half of Robert's piece of wire is equal to of Maria's wire i.e.
....(1)
Total length of the wires = 10 feet
ATQ,
....(2)
Use equation (1) in (2).

So,

Hence, this is the required solution.
1/4a-17=-15
1/4a=-15+17
1/4a=2
(1/4*4)a=(2*4)
a=8
Answer:When you are given a problem, the two sides are equal, so they are equally weighted. As long as you do the same thing on both sides, they remain the same weight. The only way that one side can become "more weight" on a side is if you make a math mistake, and thus the answer would not satisfy the original equation
Step-by-step explanation:looked it up... have a good day!