All categories

3 years ago

Can a dot plot have a gap if there is only one number in between two values??

Mathematics

1 answer:

Tanya [424]3 years ago

8 0

Yes,i think it can,hoped i helped!!!!!!!!!!!

You might be interested in

is this right?? plz answer

tekilochka [14]

Answer:maybe

Step-by-step explanation:

To answer that we need to talk about parallel universes

8 0

2 years ago

Read 2 more answers

You have a goal of saving to build up a nest egg of $625,357.24, and you are going to make regular deposits to an account that p

Delvig [45]

The monthly deposit required to save up to $625,357.24 (future value) in 40 years at a 7.2% APR is <u>$225.20</u>.

<h3>What is the monthly deposit?</h3>

The monthly deposits are the periodic savings that the investor must make to achieve future value.

The monthly deposit is compounded at the monthly annual percentage rate (APR).

We can compute the required monthly deposits using an online finance calculator as follows:

N (# of periods) = 480 months (40 years x 12)

I/Y (Interest per year) = 7.2%

PV (Present Value) = $0

FV (Future Value) = $625,357.24

<u>Results</u>:

Monthly Deposits (PMT) = $225.20

Sum of all periodic payments = $108,096 ($225.20 x 480)

Total Interest = $517,261.24

Thus, to save $625,357.24 in 40 years, you need to deposit <u>$225.20</u> monthly.

Learn more about periodic deposits (payments) at brainly.com/question/13031679

#SPJ1

6 0

1 year ago

12-1(23.28)34.67+123=? çözümü

xxMikexx [17]

Welcome
--------------

3 0

3 years ago

Read 2 more answers

Which sum will be irrational

ivolga24 [154]

<h2>Hey there! </h2>

<h3>The answer is: </h3>

<h3>Option 'B' </h3>

$\sqrt{19} + \frac{7}{2}$

<h2>BECAUSE root 19 is irrational. </h2>

5 0

3 years ago

Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal

pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and $\frac{11}{6}$ .

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form $f(x) = 0$ based on the following formula:

$x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}$

Where:

$x_{i}$ - i-th Approximation, dimensionless.

$x_{i+1}$ - (i+1)-th Approximation, dimensionless.

$f(x_{i})$ - Function evaluated at i-th Approximation, dimensionless.

$f'(x_{i})$ - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be $f(x) = x^{2}-8$ and $f'(x) = 2\cdot x$ , the resultant expression is:

$x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}$

First iteration: ( $x_{1} = 2$ )

$x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}$

$x_{2} = 2 + \frac{4}{4}$

$x_{2} = 3$

Second iteration: ( $x_{2} = 3$ )

$x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}$

$x_{3} = 2 - \frac{1}{6}$

$x_{3} = \frac{11}{6}$

7 0

3 years ago