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3 years ago

Which are the side lengths of a right triangle? Check all that apply.

Mathematics

2 answers:

S_A_V [24]3 years ago

7 1

Answer:

3, 14, and sqrt205.

2,9, and sqrt85.

Step-by-step explanation:

Check if they fit the Pythagoras theorem c^2 = a^2 + b^2:

3^2 = 9 , 14^2 = 196.

9 + 196 = 205 which is the square of sqrt205.

So this is a right angled triangle.

6^2 + 11^2 = 36 + 121

= 157 Not right-angled.

19^2 + 180^2 = 32761 Not right-angled.

3^2 + 19^2 = 370 Not right-angled.

2^2 + 9^2 = 85, So this is right angled..

earnstyle [38]3 years ago

4 0

Answer:

1 3 5

Step-by-step explanation:

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3 years ago

I really need help with this my deadline is very soon

Harman [31]

Answer:

$(3)\ y = -x$

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Step-by-step explanation:

Required

The equation in slope intercept form

Solving (3):

$m = -1$

$(x_1,y_1) =(4,-4)$

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Solving (5):

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8 0

2 years ago

What is the measure of an angle that is it’s own complement ?

ValentinkaMS [17]

A complement is angle that can be added to another to equal 90 degrees.

So two times the same number would equal 90.

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8 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

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3 years ago

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andrew11 [14]

Answer:

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Step-by-step explanation:

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