2 years ago

Solve for x 3x-1 ÷ 2 =4

Mathematics

2 answers:

Paul [167]2 years ago

6 0

Answer:

x=1.5

Step-by-step explanation:

Divide the numbers. Move the constant to the right hand side and change its sign.

3x=4+0.5

Add the numbers. Then divide both sides o fthe equation by 3. And you have your answer.

x=1.5

soldi70 [24.7K]2 years ago

4 0

X is 1.5 you do 3 times 1.5 then -1 then divide by 2

You might be interested in

2+4? I am omisha please give me answer

vladimir2022 [97]

Answer:

Step-by-step explanation:

2+4 = 6

..............

8 0

3 years ago

Read 2 more answers

Find the area of a triangle with a base of 9 feet and hypotenuse length of 13 feet

iris [78.8K]

Answer:

42.21 ft^2

Step-by-step explanation:

The formula: A=1 /2b √ c2﹣b2

c=hypotenuse

b=base

8 0

3 years ago

Simplify: 16z8-23z8 <br><br>enter the original expression if it can't be simplified

inn [45]

Answer:

The simplified version of that equation would be $-7z^{8}$ .

Step-by-step explanation:

Since $16z^{8}$ and $23z^{8}$ have the same exponent and variable, we can combine them normally.

$16z^{8}$ - $23z^{8}$ = $-7z^{8}$

4 0

4 years ago

For the function -2x²+x+1 find f(3)

nexus9112 [7]

Answer:

-14

Step-by-step explanation:

Plug 3 in for x

-2 (3)² + 3 + 1

-2 (9) + 3 + 1

-18 + 3 + 1

-14

3 0

3 years ago

Read 2 more answers

Find the perimeter of rectangle whose length is 40 and the diagonal is 41 cm<br>

Bond [772]

Answer:

Step-by-step explanation:

Given one side and diagonal of rectangle we can use Pythagorean theorem to calculate the other side of it.

$L=40\, cm\\D=41\,cm\\W=\ ?\\\\W^2+L^2=D^2\\\\W^2+40^2=41^2\\\\W^2+1600=1681\\\\W^2=81\\\\W=9$

Perimeter:

P = 2W + 2L = 2•40 + 2•9 = 80 + 18 = 98

4 0

3 years ago

Solve for x 3x-1 ÷ 2 =4​

Solve for x 3x-1 ÷ 2 =4