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3 years ago

6

Sara loves to go hiking. This week she hiked 3 miles on Monday, 4 miles on Tuesday, and 3 miles on Thursday. Last week Sara hike

d 8 miles. How many more miles did Sara hike this week than last week?

1 answer:

yKpoI14uk [10]3 years ago

6 0

For the answer to the question above, it is just simple and easy. I will the answers directly and the answer is Sara hiked 2 more miles this week than last week.

I hope my answer helped you. Have a nice day!

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How long is 75 inches in feet

Naddika [18.5K]

Answer:

6 feets mark me brainlist if i help

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2 years ago

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

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2 years ago

Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

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2 years ago

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Answer:

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Step-by-step explanation:

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You would next take 5 away from 13 and get 8.

Then you have your answer, because you cannot simplify it more because both the numbers do not have the same variable.

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Answer:

Y = -1/2x + 7/2

Step-by-step explanation:

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