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Scilla [17]
3 years ago
8

Two classes are combining to do a singing performance. The first class has 26 students and the second class has 22 students. If

the students will then be split into four singing groups, how many students will be in each of the groups?
Mathematics
2 answers:
Anettt [7]3 years ago
6 0

Answer:

12

Step-by-step explanation:

valkas [14]3 years ago
5 0
Well first lets add up all the students to see how many there are to split.

22 + 26 = 48

Now, let's split that into four groups.

48/4 = 12

So there will be 12 people in each group.
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The function h(t) = 300 – 16t represents the height of a ball (in feet) dropped from 300 feet after t seconds. What will be the
Vaselesa [24]
We are given the function expressed as:

<span>h(t) = 300 – 16t

where h is the height of the ball in time t.

We calculate the height at time equal to 2.4 seconds as follows:

</span>h(t) = 300 – 16(2.4)
h(t) = 261.6 ft

Hope this answers the question. Have a nice day.
4 0
3 years ago
7-5p+3q when p=1 and q=7
Mnenie [13.5K]

Answer:

23

Step-by-step explanation:

7 - 5p + 3q

p = 1, q = 7

Substitute in the values of "p" and "q", and solve;

7 - 5(1) + 3(7)

7 - 5 + 21

2 + 21

23

5 0
3 years ago
How many solutions does this linear system have?
Tanya [424]

Answer:

B (2.5, 0)

Step-by-step explanation:

2x - y = 5 (multiply all by 4)

8x- 4y = 20

-8x - 4y = - 20

eliminate the 4y

8x- 4y = 20

-8x - 4y = - 20

-------------------- –

16x = 40

x = 40/16 = 2.5

now we substitute x with 2.5

2x - y = 5

2(2.5) - y = 5

y = 0

8 0
3 years ago
A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title
kirill [66]
y' = \frac{dy}{dx}

seperable differential equations will have the form
\frac{dy}{dx} = F(x) G(y)

what you do from here is isolate all the y terms on one side and all the X terms on the other
\frac{dy}{G(y)} = F(x) dx
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
\int \frac{1}{G(y)} dy = \int F(x) dx&#10;&#10;

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it


In your problem,
G(y) = \sqrt{1-y^2}&#10;&#10;F(x) = 2x

so all you need to integrate is
\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx
5 0
3 years ago
2+2..................​
Nana76 [90]

Answer:

4..............21...........

4 0
2 years ago
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