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vlada-n [284]
3 years ago
14

Find the equation of a line containing the given points (4,3) and (8,1). Write the equation in slope-intercept form. Please give

step by step explanation.
Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

-1/2

Step-by-step explanation:

<u>y2-y1</u>      <u>1-3 </u>     <u> -1</u>

x2-x1      8-4      2

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Ivan and Tanya share £150 in the ratio 4: 1<br>Work out how much more Ivan gets compared to Tanya.​
Anastasy [175]

Answer:

Ivan got £90 more than Tanya.

Step-by-step explanation:

Ivan and Tanya share the amount £150 in the ratio of 4 : 1

Amount received by Ivan = 150\times \frac{4}{(4+1)}

                                          = 150\times \frac{4}{5}

                                          = £120

Similarly, amount received by Tanya = 150\times \frac{1}{(4+1)}

                                                             = £30

Difference in their amounts = 120 - 30

                                              = £90

Therefore, Ivan got £90 more than Tanya.                                                                                                        

7 0
2 years ago
According to the CDC (Centers for Disease Control and Prevention), men who smoke are 23 times more likely to develop lung cancer
Paladinen [302]

Answer:4.968

Step-by-step explanation:

21.6 percent * 23

8 0
2 years ago
Using polar coordinates, evaluate the integral which gives the area which lies in the first quadrant below the line y=5 and betw
vfiekz [6]

First, complete the square in the equation for the second circle to determine its center and radius:

<em>x</em> ² - 10<em>x</em> + <em>y</em> ² = 0

<em>x</em> ² - 10<em>x</em> + 25 + <em>y </em>² = 25

(<em>x</em> - 5)² + <em>y</em> ² = 5²

So the second circle is centered at (5, 0) with radius 5, while the first circle is centered at the origin with radius √100 = 10.

Now convert each equation into polar coordinates, using

<em>x</em> = <em>r</em> cos(<em>θ</em>)

<em>y</em> = <em>r</em> sin(<em>θ</em>)

Then

<em>x</em> ² + <em>y</em> ² = 100   →   <em>r </em>² = 100   →   <em>r</em> = 10

<em>x</em> ² - 10<em>x</em> + <em>y</em> ² = 0   →   <em>r </em>² - 10 <em>r</em> cos(<em>θ</em>) = 0   →   <em>r</em> = 10 cos(<em>θ</em>)

<em>y</em> = 5   →   <em>r</em> sin(<em>θ</em>) = 5   →   <em>r</em> = 5 csc(<em>θ</em>)

See the attached graphic for a plot of the circles and line as well as the bounded region between them. The second circle is tangent to the larger one at the point (10, 0), and is also tangent to <em>y</em> = 5 at the point (0, 5).

Split up the region at 3 angles <em>θ</em>₁, <em>θ</em>₂, and <em>θ</em>₃, which denote the angles <em>θ</em> at which the curves intersect. They are

<em>θ</em>₁ = 0 … … … by solving 10 = 10 cos(<em>θ</em>)

<em>θ</em>₂ = <em>π</em>/6 … … by solving 10 = 5 csc(<em>θ</em>)

<em>θ</em>₃ = 5<em>π</em>/6  … the second solution to 10 = 5 csc(<em>θ</em>)

Then the area of the region is given by a sum of integrals:

\displaystyle \frac12\left(\left\{\int_0^{\frac\pi6}+\int_{\frac{5\pi}6}^{2\pi}\right\}\left(10^2-(10\cos(\theta))^2\right)\,\mathrm d\theta+\int_{\frac\pi6}^{\frac{5\pi}6}\left((5\csc(\theta))^2-(10\cos(\theta))^2\right)\,\mathrm d\theta\right)

=\displaystyle 50\left\{\int_0^{\frac\pi6}+\int_{\frac{5\pi}6}^{2\pi}\right\} \sin^2(\theta)\,\mathrm d\theta+\frac12\int_{\frac\pi6}^{\frac{5\pi}6}\left(25\csc^2(\theta) - 100\cos^2(\theta)\right)\,\mathrm d\theta

To compute the integrals, use the following identities:

sin²(<em>θ</em>) = (1 - cos(2<em>θ</em>)) / 2

cos²(<em>θ</em>) = (1 + cos(2<em>θ</em>)) / 2

and recall that

d(cot(<em>θ</em>))/d<em>θ</em> = -csc²(<em>θ</em>)

You should end up with an area of

=\displaystyle25\left(\left\{\int_0^{\frac\pi6}+\int_{\frac{5\pi}6}^{2\pi}\right\}(1-\cos(2\theta))\,\mathrm d\theta-\int_{\frac\pi6}^{\frac{5\pi}6}(1+\cos(2\theta))\,\mathrm d\theta\right)+\frac{25}2\int_{\frac\pi6}^{\frac{5\pi}6}\csc^2(\theta)\,\mathrm d\theta

=\boxed{25\sqrt3+\dfrac{125\pi}3}

We can verify this geometrically:

• the area of the larger circle is 100<em>π</em>

• the area of the smaller circle is 25<em>π</em>

• the area of the circular segment, i.e. the part of the larger circle that is bounded below by the line <em>y</em> = 5, has area 100<em>π</em>/3 - 25√3

Hence the area of the region of interest is

100<em>π</em> - 25<em>π</em> - (100<em>π</em>/3 - 25√3) = 125<em>π</em>/3 + 25√3

as expected.

3 0
2 years ago
X = 4. 5x +23x^3 - 360.
Zinaida [17]

Missing: 360 ‎| ‎Must include: ‎360

look at

https://www.google.com/search?q=x+%3D+4.+5x+%2B23x%5E3+-+360&rlz=1CAJAIV_enUS838&oq=x+%3D+4.+5x+%2B23x%5E3+-+360&aqs=chrome..69i57&sourceid=chrome&ie=UTF-8&safe=active&ssui=on

4 0
3 years ago
Read 2 more answers
Is this proportional
love history [14]
What is proportional?
Can you copy and paste the question or link the website?

I ***POSSIBLY*** can TRY to help you
6 0
3 years ago
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