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vlada-n [284]
3 years ago
14

Find the equation of a line containing the given points (4,3) and (8,1). Write the equation in slope-intercept form. Please give

step by step explanation.
Mathematics
1 answer:
k0ka [10]3 years ago
4 0

Answer:

-1/2

Step-by-step explanation:

<u>y2-y1</u>      <u>1-3 </u>     <u> -1</u>

x2-x1      8-4      2

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How do you find the <br> y-intercept and the slope for number 11
Sophie [7]
The first step is to find the slope. Use the slope formula

m = (y2-y1)/(x2-x1)

The two points are (x1,y1) = (-1,5) and (x2,y2) = (2,-1)

So,
x1 = -1
y1 = 5
and
x2 = 2
y2 = -1
will be plugged into the slope formula to get...
m = (y2-y1)/(x2-x1)
m = (-1-5)/(2-(-1))
m = (-1-5)/(2+1)
m = (-6)/(3)
m = -2

The slope is -2

Use m = -2 and one of the points to find the y intercept b. I'll use the point (x,y) = (-1,5) ---> x = -1, y = 5

y = mx+b ... slope intercept form
5 = -2*(-1)+b
5 = 2+b
5-2 = 2+b-2
3 = b
b = 3

The y intercept is 3

-----------------------------------

m = -2 is the slope
b = 3 is the y intercept

Therefore y = mx+b turns into y = -2x+3 as the equation that goes through the two points
6 0
3 years ago
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