Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
false, false, true, false
The answer is
x=10+2y
Steps:
2(x-2y)=20
x-2y=20/2 (in fraction form 20/2)
x-2y=10
X=10+2y