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Usimov [2.4K]
3 years ago
14

Hannah was saving for a new snowboard. the one she wanted originally cost $ 109. it had been marked down 10% and then another 12

%. a tax of 6% was added to final sale price. if Hannah had $90, did she have enough to buy the snowboard? Explain your answer.
Mathematics
2 answers:
Zigmanuir [339]3 years ago
6 0
First you would find the 10% discount of $109, which is equal to 90% of $109 or .9*$109 = $98.10.

You would then take $98.10 and find the 12% discount with is equal to 88% of $98.10 or .88*$98.10 = $86.33

Then you would add a 6% sales tax would would be 106% of $86.33 or 1.06*$86.33 = $91.51

Thus, she did not have enough to buy, and was $1.51 short. 
Semenov [28]3 years ago
3 0
So marked down 10 then 12 so 10+12=22
mark down total is 22%
100-22=78
78% of 109=0.78 times 109=85.02
tax of 6%
6+100=106%

85.02 times 1.06=90.1212 or about 90.12
90<90.12
no she is short 12 cents
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The Canada Urban Transit Association has reported that the average revenue per passenger trip during a given year was $1.55. If we assume a normal distribution and a standard deviation of 5 $0.20, what proportion of passenger trips produced a revenue of Source: American Public Transit Association, APTA 2009 Transit Fact Book, p. 35.

a. less than $1.55?

b. between $1.15 and $1.95? c. between $1.35 and $1.75? d. between $0.95 and $1.55?

Given that :

Mean (m) = 1.55

Standard deviation (s) = 0.20

a. less than $1.55?

P(x < 1.55)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

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p(Z < 0) = 0.5 ( Z probability calculator)

b. between $1.15 and $1.95?

P(x < 1.15)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.15 - 1.55) / 0.20 = - 2

p(Z < - 2) = 0.02275 ( Z probability calculator)

P(x < 1.95)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.95 - 1.55) / 0.20 = 2

p(Z < - 2) = 0.97725 ( Z probability calculator)

0.97725 - 0.02275 = 0.9545

c. between $1.35 and $1.75?

P(x < 1.35)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.35 - 1.55) / 0.20 = - 1

p(Z < - 2) = 0.15866 ( Z probability calculator)

P(x < 1.75)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (1.75 - 1.55) / 0.20 = 1

p(Z < - 2) = 0.84134 ( Z probability calculator)

0.84134 - 0.15866 = 0.68268

d. between $0.95 and $1.55?

P(x < 0.95)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (0.95 - 1.55) / 0.20 = - 3

p(Z < - 3) = 0.0013499 ( Z probability calculator)

P(x < 1.55)

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Z = (x - m) / s

Z = (1.55 - 1.55) / 0.20 = 0

p(Z < 0) = 0.5 ( Z probability calculator)

0.5 - 0.0013499 = 0.4986501

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