Question

A picture frame 4 inches wide by 6.5 inches high has a 3 inch by 5 inch photograph place in the center. What is the area of the frame?

Answer 1

Answer:

$A_f=11~inches$

Step-by-step explanation:

Area of a Rectangle

A rectangle of width W and height H has an area of:

A = W.H

We have one rectangle inside another. The first rectangle corresponds to the frame and its contents. The second rectangle corresponds to the photograph.

The area of the frame without its contents is the difference between both areas:

$A_f = A_e-A_i$

Where Ae is the external area of the frame, and Ai is the internal frame of the photograph.

The frame has W=4 inches and L=6.5 inches, thus:

$A_e=4~inches*6.5~inches$

$A_e=26~inches$

The photograph has W=3 inches and L=5 inches, thus:

$A_i=3~inches*5~inches$

$A_i=15~inches$

The area of the frame is:

$A_f = 26 - 15 = 11~inches$

$\mathbf{A_f=11~inches}$

Answer 2

Area =  l × w

=  6.5 × 4

=  26 feet2