1: 3.2
2: B. 1.6
3: C. 6.4
4: D. 17.92
I'm unable to see the table for 5, are you able to attach it?
The answer is d as for any given length you could have any given volume by altering the cross sectional area of the pool and vice versa
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is

, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 =
8.88 mg.</span>
Answer: -5.27 + (-3.32) = -8.59 and -5.6 + 27.4 = 21.8
Step-by-step explanation: Have a nice day bro!✌️