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andrey2020 [161]
3 years ago
6

Estimate 726 times 5

Mathematics
1 answer:
Rom4ik [11]3 years ago
6 0

700 times 5 = 3500 or 726 times 5 estimated =4000 hope this helps

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There are 33 of them altogether and pay £311 in total. How many kids are in the family? Adults pay £15 and kids pay £7
Marrrta [24]

Answer:

Step-by-step explanation

  1. Let x be the number of adults and y the number of kids

We can then write this two equations :

          x+y= 33

          15x+7y= 311

  • let's solve the two eaquations

to do that we should combine them both in a way that help us get rid of one of the variables.

             Let's multiply the first equation by -7 to get rid of y by adding it to thr second equation

             -7x-7y= -231

        now add both equations .

              15x+7y-7x-7y=311-231

    we get :  8x = 80

as you notice y is gone and we get a classic easy equation to solve

                x= 80/8

                   = 10

so the number of adults is 10

let's go back to the first equation ( x+y= 33) and replace x with 10

                10+y= 33

                  y= 33-10

                     =23

let's check using the second equation :

            (10*15)+(23*7) = 311

that is true

so :

  •  the number of adults is 10
  • the number of kids is 23
4 0
3 years ago
Craig made a mobile using geometric shapes including triangles shaped as shown. For what value of X and Y can you use a triangle
PolarNik [594]

Answer:

x = 3

y = 8

Step-by-step explanation:

In the given triangle FGH,

m∠F + m∠G + m∠H = 180° [Triangle sum theorem]

60° + 90° + m∠H = 180°

m∠H = 30°

If the given triangles FGH and TUV are congruent, their corresponding sides will be equal in measure.

m∠F = m∠T

7y + 4 = 60°

7y = 56

y = 8

GH ≅ UV

8x - 12 = 12

8x = 24

x = 3

4 0
3 years ago
Use the distributive property to simplify 27-9x+15y
faust18 [17]
27-9x+15y=3(9-3x+5y)
6 0
3 years ago
54) |1-2/3x|<1
Naily [24]

|a| < b\iff a < b\ \wedge\ a > -b\\\\|a| > b\iff a > b\ \vee\ a < -b

\left|1-\dfrac{2}{3}x\right| < 1\iff1-\dfrac{2}{3}x < 1\ \wedge\ 1-\dfrac{2}{3}x > -1\ \ \ |\text{subtract 1 from both sides}\\\\-\dfrac{2}{3}x < 0\ \vedge\ -\dfrac{2}{3}x > -2\ \ \ \ |\text{change the signs}\\\\\dfrac{2}{3}x > 0\ \wedge\ \dfrac{2}{3}x < 2\ \ \ \ |\text{multiply both sides by 3}\\\\2x > 0\ \wedge\ 2x < 6\ \ \ \ |\text{divide both sides by 2}\\\\x > 0\ \wedge\ x < 3\to0 < x < 3\to x\in(0,\ 3)

4 0
3 years ago
Write the number of permutations in factorial form. Then simplify. J K L M N O P
guajiro [1.7K]

Answer:

The number of permutations of the group of letters given (J, K, L, M, N, O and P) is 7! = 7 . 6 . 5 . 4 . 3 . 2 . 1 = 5,040.

Step-by-step explanation:

The number of permutations without repetition is the number of possible sequences that can occur if we take the letters one by one and is calculated with the factorial of the total number of letters in the group.

Before starting we have 7 possibilities, one for each letter. Once the first letter is chosen randomly, we will have 6 possibilities, after taking the third letter we will have 5 possibilities, and so on.

In total the total number of possibilities to obtain the 7 letters in a certain order are 7 by 6 by 5 by 4 by 3 by 2 by 1, sayed in other words factorial of 7 (7!). The result of the multiplication gives 5,040.

In short we can get the seven letters in 5,040 different sequences.

7 0
3 years ago
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