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Vladimir [108]
3 years ago
5

Make a conjecture: How many solutions does a quartic equation x 4 + ax 3 + bx 2 + cx + d = 0 have? Explain.

Mathematics
1 answer:
Ratling [72]3 years ago
5 0

Answer:

Four

Step-by-step explanation:

The degree of a polynomial is the highest of the degree of the monomials with non-zero co-efficient. In this problem we are given the polynomial:

                 $ x^4 + ax^3 + bx^2 + cx + d = 0 $

The degree of the polynomial is 4.

For a polynomial of <em>n- degree </em>we have <em>n solutions counting multiplicity</em>.

So for this four degree polynomial we would have 4 solutions. Could be real or complex depending on the equation.

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Answer:

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Step-by-step explanation:

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By applying sine rule in the ΔYPZ,

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Therefore, area of the given triangle = \frac{1}{2}(18)(14)sin(38)

By applying sine rule in ΔYPZ,

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Area of ΔXYZ = \frac{1}{2}(18)(10)sin(58)

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