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Vladimir [108]
2 years ago
5

Make a conjecture: How many solutions does a quartic equation x 4 + ax 3 + bx 2 + cx + d = 0 have? Explain.

Mathematics
1 answer:
Ratling [72]2 years ago
5 0

Answer:

Four

Step-by-step explanation:

The degree of a polynomial is the highest of the degree of the monomials with non-zero co-efficient. In this problem we are given the polynomial:

                 $ x^4 + ax^3 + bx^2 + cx + d = 0 $

The degree of the polynomial is 4.

For a polynomial of <em>n- degree </em>we have <em>n solutions counting multiplicity</em>.

So for this four degree polynomial we would have 4 solutions. Could be real or complex depending on the equation.

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How do I solve this math problem 5/6n=10​
GaryK [48]

Answer:

Step-by-step explanation:

5/6n=10​

Cross multiply

5 = 10×6n

5 = 60n

n = 5/60

n = 1/12

7 0
3 years ago
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Find the solution to the equation.
Mekhanik [1.2K]

Answer:

-7

Step-by-step explanation:

30-16= -5n +3n

14 = -2n

multiplying both by half,u have -

7 = -n

multiply both by -1

7 = n

3 0
2 years ago
Julie buys a pair of earrings for $7. Now she would like to the same earrings for 2 friends. How much will she spend for all 3 p
ankoles [38]
The easiest way to do this is to multiple 7 and 3, which gives you 21. Julie will spend $21 on the gifts.
5 0
2 years ago
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What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i
Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>

We can model this as a binomial random variable, with p=0.57 and n=14.

P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\

P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\

P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\

P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886

7 0
2 years ago
I NEED HELP ASAP PLEASE!!!!!!
Colt1911 [192]
Use an app on your phone just make sure you pick a gods one it will give you the answer I am not that good at math tho
6 0
3 years ago
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