U= 9.4m/s
v= -7.4m/s (Negative sign because it is in the opposite direction as he is rolling back)
t= ?
s= ?
a= ?
Now, a= v-u/t
= -7.4-9.4÷3
=-5.6
By the second equation of motion.
s= ut+1÷2at*2 ( *2 is the power)
s= 9.4×3+1÷2×-5.6×3*2
= 28.2 +(-25.2)
=3
Therefore s or the distance travelled is 3m.
Answer:
A = 139.25
Step-by-step explanation:
Answer:
42 mph
Step-by-step explanation:
From 2 p.m. to 6 p.m. 4 hours passed, so the truck and the motorcycle were on the road for 4 hours until they met.
Motorcycle in 4 hours at a constant speed of 45 mph travelled
The distance between the motorcycle and the truck is 348 miles, so the truck travelled
If x mph is truck's speed, then
Answer:
The probability is 0.694
Step-by-step explanation:
Let the probability of getting a car washed be
P(W) = 72% = 0.72
Let the probability of getting a car vacuumed be
P(V) = ?
Probability of getting car washed and vacuumed is P(W n V) = 50% = 0.5
From Bayes’ theorem
P(V|W) is the probability that a customer gets their car vacuumed given that they are getting it washed
So mathematically;
P(V|W) = P(V n W)/P(W)
= 0.5/0.72 = 0.694
If he once traveled 36 hours and he takes 6 hour trips you do
10x3=30 so every six hours he takes 30 minute brakes then 36 divided by 6 equlas 6 you would do 30x6= the answer!!! (Btw i do 6th grade math)
