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Aloiza [94]
3 years ago
9

A baseball hat for $22.90 at 5% sales tax

Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0
5+100= 105% means part out of a 100
105%= 105/100=1.05.
105% of 22.90 ×1.05 = 24.045
Round it off to $24.05
Answer is $24.05
Hoping this helps
vovikov84 [41]3 years ago
5 0
I think it's $21.75 with tax
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How old am I if 689 reduced by 5 times my age is 464? Write and Solve an Equation with an answer.
ludmilkaskok [199]

Answer:

45

Step-by-step explanation:

689 - 464 = 225

225 /5 = 45

7 0
3 years ago
Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:
Vikentia [17]

Answer:

a

   \= x  = 18.5  ,  \sigma =  5.15

b

 15.505 < \mu <  21.495

c

 14.93 < \mu <  22.069

Step-by-step explanation:

From the question we are are told that

    The  sample data is  21, 14, 13, 24, 17, 22, 25, 12

     The sample size is  n  = 8

Generally the ample mean is evaluated as

        \= x  =  \frac{\sum x  }{n}

        \= x  =  \frac{  21 + 14 + 13 + 24 + 17 + 22+ 25 + 12  }{8}

         \= x  = 18.5

Generally the standard deviation is mathematically evaluated as

         \sigma =  \sqrt{\frac{\sum (x- \=x )^2}{n}}

\sigma =  \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}

\sigma =  5.15

considering part b

Given that the confidence level is  90% then the significance level is evaluated as

         \alpha  =  100-90

         \alpha  = 10\%

         \alpha  = 0.10

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.645

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.645  *  \frac{5.15 }{\sqrt{8} }

=>     E =  2.995

The 90% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 -  2.995 < \mu <  18.5 +  2.995

       15.505 < \mu <  21.495

considering part c

Given that the confidence level is  95% then the significance level is evaluated as

         \alpha  =  100-95

         \alpha  = 5\%

         \alpha  = 0.05

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.96

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.96  *  \frac{5.15 }{\sqrt{8} }

=>     E = 3.569

The 95% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 - 3.569 < \mu <  18.5 +  3.569

       14.93 < \mu <  22.069

8 0
3 years ago
Joshua finds the perimeter of the following composite figure composed of a square and right triangle so that a braid may be cut
Bumek [7]

The perimeter of a shape is the sum of its side lengths.

<em>Joshua miscalculated the third length of the triangle</em>

First, we calculate the third length (x) of the triangle.

Because the triangle is right-angled, we can make use of Pythagoras.

So we have:

x^2 = 7^2 + 7^2

x^2 = 2(7^2)

Take square roots of both sides

x = \sqrt{2(7^2)

x = 7\sqrt{2

The other shape in the figure is a square.

So, the perimeter (P) is

P = 7 + x + x + x + 7 ---- i.e. the sum of the visible lengths

So, we have:

P = 7 + 7\sqrt2 + 7\sqrt2 + 7\sqrt2+ 7

Evaluate like terms:

P = 14 + 21\sqrt2

Hence, Joshua's error is that:

<em>He miscalculated the third length of the triangle</em>

Read more about perimeters at:

brainly.com/question/6465134

4 0
2 years ago
What is the interquartile Range for the following data set? {5,6,7,3,9,8,3,1,6,7,7}
mrs_skeptik [129]
To find the interquartile range of the data, you get both quartile one (1) and two (2) and subtract the larger number from the lower number.

Q3 - Q1 = Interquartile range

Your answer, in turn, would be... 
4

8 0
3 years ago
can someone please help me?!
Setler [38]
Angle 2 = 46°

Angle 3 = 180-46=134°
6 0
2 years ago
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