A(1) = 6 = d + c
<span>a(4) = 33 = 4d + c </span>
<span>3d = 27=> d=9 </span>
<span>c = -3 </span>
<span>a(2) = 9(2) - 3 = 15 </span>
<span>a(3) = 15 + 9 = 24</span>
Answer:
$2.75
Step-by-step explanation:
Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be 
, where 
is the stopping distance measured in metres and 
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of 
.
2) Add the function 
.
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
we find the average height of each height first,
t¹= (120+124)/2
=244/2
=122
t²= (124+128)/2
t²= 252/2
t²= 126
t³= (128+132)/2
t³= 260/2
t³= 130
t⁴= (132+136)/2
t⁴= 268/2
t⁴ =134
t⁵= (136+140)/2
t⁵= 276/2
t⁵= 138
so multiplying each height by its frequency we can find the total height, so we have..
total height= (122*7)+(126*8)+(130*13)+(134*9)+(138*3)
= 854+1008+1690+1206+414
= 5172
mean height = total height/total frequency
= 5172/40
=129.3
Shifted up
For example: if f(x) = x^2 + 4, the parent function has a vertex at (0,0), but the +4 shifts the graph up 4 units on the y-axis so the vertex would be (0,4)
